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slega [8]
3 years ago
11

Find ΔHrxn for the following reaction: 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)

Chemistry
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

ΔH°rxn = -827.5 kJ

Explanation:

Let's consider the following balanced equation.

2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)

We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]

ΔH°rxn = -827.5 kJ

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A 13.8 g sample of X reacts with a sample of Y to form 68.3 g of XY.What is the mass of Y that reacted
alexandr402 [8]

54.5 grams of Y reacted with 13.8 g sample of X to form 68.3 g of XY.

Explanation:

In chemical reaction the mass remains conserved until the dissipation or lost is shown. In the question it is mentioned that 13.gm of X reacts with some amount of Y to form a product XY of mass 68.3 grams.

The reaction given is addition reaction in which two elements react to for a compound.

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So, in the chemical reaction value of mass is put as

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Explanation:

A covalent compound is defined as a compound formed by sharing of electrons.

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