Answer:
t = 3w/gk
y = w²/gk²(2+e^-gkt/t)
Explanation:
The detailed step by step solution can be found in the attachment below.
Vt = W/k. It is the velocity of the body when the drag force = the weight of the particle.
I steps have been explaine6in the attachments below.
Answer:
d = 10.076 m
Explanation:
We need to obtain the velocity of the ball in the y direction
Vy = 24.5m/s * sin(35) = 14.053 m/s
To obtain the distance, we use the formula
vf^2 = v0^2 -2*g*d
but vf = 0
d = -vo^2/2g
d = (14.053)^2/2*(9.8) = 10.076 m
Answer:
(B) the increase in the car's potential energy is 3,660,000 J
Explanation:
Given;
mass of the car, m = 1,000 kg
height through the car was drove, h = 366 m
acceleration due to gravity, g = 10 m/s²
The increase in the car's potential energy is calculated as;
P.E = mgh
P.E = 1000 x 10 x 366
P.E = 3,660,000 J
Therefore, the increase in the car's potential energy is 3,660,000 J
It's the angle made by the incident ray when it's perpendicular to the surface. (Perpendicular lines are the lines that form a graph or like a 90-degree angle)
Answer:
From Savos point of view, Gadros appear not to be moving
Explanation:
The given parameters are;
The distance between Godric and Savos = A few meters
The location of Godric and Savos = One end of the field
The location pf Peter = The other end pf the field
The speed with which Godric and Savos are moving towards Peter = 4 m/s
Let the positive x-direction be the direction in which Godric and Savos are moving
Therefore;
The speed and direction with which Godric is moving = The speed and direction with which Savos is moving = 4·i m/s
From Savos point of view, the relative speed with which Godric is moving = (The speed and direction in which Godric is moving) - (The speed and direction in which Savos is moving) = 4·i m/s - 4·i m/s = 0 m/s
Therefore, from Savos point of view, the relative speed with which Godric is moving = 0 m/s or Gadros appears stationary or not to moving.
