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____ [38]
4 years ago
7

Where would you most likely find an electrostatic precipitator being used?

Physics
1 answer:
Ronch [10]4 years ago
8 0
In paint industry ..and also in steel industry
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Calculate the equivalent resistance of the circuit below.
expeople1 [14]

Answer:

30Ω

Explanation:

To calculate the equivalent resistance in the circuit, do the following:

Step 1:

10Ω and 20Ω are in series connection. Therefore their equivalent is: 10 + 20 = 30Ω

Step 2:

The equivalent resistance (30Ω) obtained from the above is in parallel connection with 30Ω resistance shown in the diagram above.

Therefore their equivalent is given by:

1/30 + 1/30 = 2/30 = 1/15.

Now invert to obtain the equivalent

Therefore, the equivalent is 15Ω

Step 3:

Determination of the overall equivalent of the resistance of the circuit.

The new equivalent resistance 15Ω obtained above is in series connection with 15Ω resistance in the diagram above.

Therefore their equivalent is given by:

15Ω + 15Ω = 30Ω

Therefore, the equivalent resistance in the circuit is 30Ω

7 0
3 years ago
The precision of a laboratory instrument is ± 0.05 g. The accepted value for your measurement is 7.92 g. Which measurements are
skelet666 [1.2K]

Answer:

7.89 7.91

Explanation:

The ranges of measurement lie between 7.92-0.05 and 7.92+0.05

7.87g and 7.97g

3 0
3 years ago
Read 2 more answers
Which part of an Adam is actively exchanged or shared in a chemical bond?
Lemur [1.5K]
Atom* the particles are (Electrons)
5 0
3 years ago
For an electron, magnitude of force on it<br> is<br> Select one<br> • Bev<br> bev<br> Be<br> BIL
maw [93]

Answer:

F = Bev

Explanation:

B is magnetic field density

e is the electron charge

v is the electron velocity

6 0
3 years ago
Two sailboats leave a harbor in the bahamas at the same time. the first sails at 23 mph in a direction 330°. the second sails at
pishuonlain [190]

First, let us calculate the total distance that each have taken after 2 hours.

Let’s say that:

A = sailboat which sails at 23 mph in a direction 330°

B = sailboat which sails at 34 mph in a direction 190°

Calculating for distances:

dA = 23 mph (2 hours) = 46 miles

dB = 34 mph (2 hours) = 68 miles

Imagining a Cartesian coordinate, the angle θ between the two sailboats is simply the difference:

θ = 330° - 190°

θ = 140°

We know that from the law of cosines:

c^2 = a^2 + b^2 – 2 a*b*cos θ

Therefore the distance between the two after 2 hours, C, is:

C^2 = 46^2 + 68^2 – 2 (46) (68) cos(140)

<span>C = 107.39 miles</span>

7 0
4 years ago
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