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MrRa [10]
3 years ago
10

Frank does 2400J of work in climbing a set of stairs. If he does the work in 6 seconds, what is his power output?

Physics
1 answer:
timurjin [86]3 years ago
4 0
Power = Work Done / Time taken

         Where Work Done is Joules, and Time is in Seconds, Power is in Watts

            = 2400 J / 6 seconds

            = 400 Watts

The power output is 400 Watts.
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Which of the following is a heterogeneous mixture? A. salt B. dye in water C. sugar water D. a garden salad
dedylja [7]
D garden salad : )

A heterogenous mixture can be easily taken apart visually/physically
7 0
2 years ago
What is the magnitude of the momentum of a 3400 kg airplane traveling at a speed of 450 miles per hour?
Vitek1552 [10]

Answer:

The magnitude of momentum of the airplane is 6.83\times 10^5\ kg-m/s.

Explanation:

Given that,

Mass of the airplane, m = 3400 kg

Speed of the airplane, v = 450 miles per hour

Since, 1 mile per hour = 0.44704 m/s

v = 201.16 m/s

We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,

p=mv

p=3400\ kg\times 201.16 \ m/s

p=683944\ kg-m/s

or

p=6.83\times 10^5\ kg-m/s

So, the magnitude of momentum of the airplane is 6.83\times 10^5\ kg-m/s. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
2 years ago
What is the main difference between an internal cumbustion engine and a external combination engine
aleksandrvk [35]
Internal and external combustion engines are two types of heat engines: they convert thermal energy into mechanical energy. The main difference between internal and external combustion engine is that in internal combustion engines, the working fluid burns inside the cylinder, whereas in external combustion engines, combustion takes place outside the cylinder and heat is then transferred to the working fluid.
5 0
3 years ago
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WINSTONCH [101]

Answer:

r=200m

Explanation:

From the question we are told that:

Charges:

Q_1=8.0mC

Q_2=2.0mC

Q_3=8.mC

Distance d=300m

Generally the equation for Force is mathematically given by

F=\frac{kq_1q_2}{r^2}

Therefore

F_{32}=F_{31}

\frac{q_2}{(300-r)^2}=\frac{q_1}{r^2}

\frac{2*10^{-3}}{(300-r)^2}=\frac{8*10^{-3}}{r^2}

r=2(300-r)

r=200m

8 0
2 years ago
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