Answer:
2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)
Explanation:
A thermochemical equation must show the formation of 1 mol of a substance from its elements in their most stable state,.
The only equation that meets those conditions is the last one.
A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.
C is wrong because Li⁺ and SO₄²⁻ are not elements.
D is wrong because it shows the formation of 8 mol of Li₂SO₄.
They had fresher breathe because their breathe may have been bad before.
Answer:
ΔG = -6.5kJ/mol at 500K
Explanation:
We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:
ΔG = ΔH - TΔS
Computing the values in the problem:
ΔG = ?
ΔH = 2kJ/mol
T = 500K
And ΔS = 0.017kJ/(K•mol)
Replacing:
ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)
ΔG = 2kJ/mol - 8.5kJ/mol
<h3>ΔG = -6.5kJ/mol at 500K</h3>
