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3 years ago

An example of a physical property of an element is the element's ability to what?

Chemistry

1 answer:

anygoal [31]3 years ago

8 0

Explanation:

Appearance, melting point, density, solubility, polarity

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For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen,

BartSMP [9]

A) 4400 kj of heat released into surroundings

<h3>Further explanation</h3>

Reaction

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ

Reaction exothermic( ∆H=-, released heat to surrounding) and for combustion of 1 mole of C3H8

So for two moles of C3H8, the enthalpy :

$\tt -2200\times 2=-4400~kJ$

7 0

3 years ago

Hydrogen is special because it can act like two groups, _____ and _____

Vedmedyk [2.9K]

Answer: gas and alkaline earth metal

Explanation:

4 0

3 years ago

I haven’t shifted before I tried like once a few months ago and I keep wanting to shift and last night I had a dream I did is th

shepuryov [24]

Yes a sign of shifting is having a dream about ur dr

3 0

3 years ago

Suppose that some FeSCN2+ is added to the above solution to shift the equilibrium. When equilibrium is re-established, the follo

kiruha [24]

Explanation:

The given reaction equation will be as follows.

$[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]$

Let is assume that at equilibrium the concentrations of given species are as follows.

$[Fe^{3+}] = 8.17 \times 10^{-3}$ M

$[SCN^{-}] = 8.60 \times 10^{-3}$ M

$[FeSCN^{2+}] = 6.25 \times 10^{-2}$ M

Now, first calculate the value of $K_{eq}$ as follows.

$K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}$

= $\frac{8.17 \times 10^{-3} \times 8.60 \times 10^{-3}}{6.25 \times 10^{-2}}$

= $11.24 \times 10^{-4}$

Now, according to the concentration values at the re-established equilibrium the value for $[FeSCN^{2+}]$ will be calculated as follows.

$K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}$

$11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}$

$[FeSCN^{2+}] = 5.66 \times 10^{-2}$ M

Thus, we can conclude that the concentration of $[FeSCN^{2+}]$ in the new equilibrium mixture is $5.66 \times 10^{-2}$ M.

7 0

3 years ago

A sample of table sugar (sucrose c12h22o11) has a mass of 3.115 g

attashe74 [19]

Hey there:

a) atomic mass:

Carbon =12.0107 g/mol

Hydrogen = 1.00794 g/mol

Oxygen = 15.9994 g/mol

Therefore:

C12H22O11 =

12 * 12.0107 + 1 * 1.00794 + 16 * 15.9994 => 342.29648 g/mol

__________________________________________________________

b) number of moles:

n = m / mm

n = 3.115 / 342.29648

n = 0.0091 moles

________________________________________________

hope this helps!

6 0

3 years ago