Answer:
okay let me know when i can help, ill be happy too help
Answer: 31.55 g
Explanation:
- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.
- 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),
so 1 mole of (F2) with 37.98 g/mol → 6.02×10^23 molecules.
- Using cross multiplication,
37.98 g/mol of (F2) → 6.02 ×10^23 molecules
? → 5.00 ×10^23 molecules
Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..
<span>Answer:
I'm assuming the question is asking when it "jumps" from level 2 to level 1. In which case: 1/λ = Rh(1/nf^2 - 1/nfi^2) = 1.10x10^7 (1/1^2 - 1/2^2) = 1.10x10^7 ( 1 - 0.25) = 1.10 x10^7 (0.75) λ = 1.21 x 10^-7 m The wavelength produced will be about 1.21 x 10^ -7 m, or 121 nm.</span>
Data Given:
Moles = n = 3.91 mol
Pressure = P = 5.35 atm
Temperature = T = 323 K
Volume = V = ?
Formula used: Ideal Gas Equation is used,
P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm
V = 19.36 L
The correct answer is Chemical weathering.
~ hope this helps! ❤️
