convert 40db to standard gain
AL=10^40/20=100
calculate total voltage gain
=AL×RL/RL+Ri
=83.33
38.41 DB
calculate power
Pi=Vi^2/Ri Po=Vo^2/RL
power gain= Po/Pi
=13.90×10^6
Answer:
24.72 kwh
Explanation:
Electric energy=potential energy=mgz where m is mass, g is acceleration due to gravity and z is the elevation.
Substituting the given values while taking g as 9.81 and dividing by 3600 to convert to per hour we obtain
PE=(108*9.81*84)/3600=24.72 kWh
Answer:
The current through the coil is 2.05 A
Explanation:
Given;
number of turns of the coil, N = 1
radius of the coil, r = 9.8 cm = 0.098 m
magnetic moment of the coil, P = 6.2 x 10⁻² A m²
The magnetic moment is given by;
P = IA
Where;
I is the current through the coil
A is area of the coil = πr² = π(0.098)² = 0.03018 m²
The current through the coil is given by;
I = P / A
I = (6.2 x 10⁻² ) / (0.03018)
I = 2.05 A
Therefore, the current through the coil is 2.05 A
Answer:
Yes
Explanation:
Given Data
Temprature of source=750°c=1023k
Temprature of sink =0°c=273k
Work produced=3.3KW
Heat Rejected=4.4KW
Efficiency of heat engine(η)=
and
Heat Supplied 
η=
η=42.85%
Also the maximum efficiency of a heat engine operating between two different Tempratures i.e. Source & Sink
η=1-
η=1-
η=73.31%
Therefore our Engine Efficiency is less than the maximum efficiency hence the given claim is valid.
Answer:
Temperature
Explanation:
In an ideal gas the specific enthalpy is exclusively a function of Temperature only this can be also written as h = h(T)
A gas is said be ideal gas if obeys PV= nRT law
And in a ideal gas both internal energy and specific enthalpy are a function of Temperature only. Therefore the constant volume and constant pressure specific heats Cv and Cp are also function of temperature only.
