Answer:
aA
Explanation:
air conditioning performance check requires the use of aA.
Hope this helps!
Answer:
Civil Engineering.
Explanation:
Civil Engineering is a field of engineering study that deals with professional practising in designing and developing infrastructures such as transport system and networks, buildings, etc.
<u>Civil engineering is regarded as the second--oldest form of engineering studies in the field of engineering.</u>
<u>A person who studies civil engineering is able to design and develop major projects in transportations system such as road construction, bridges, airports, tunnels, etc.</u>
So, Danny, who is interested in studying transporation networks and system should opt for studying civil engineering.
Answer:
Glycogen is the primary energy source for muscle and liver cells.
Explanation:
Glycogen is a readily mobilized storage form of glucose. It is a very large, branched polymer of glucose residues that can be broken down to yield glucose molecules when energy is needed. Most of the glucose residues in glycogen are linked by α-1,4-glycosidic bonds. Branches at about every tenth residue are created by α-1,6-glycosidic bonds.
Glycogen is not as reduced as fatty acids are and consequently not as energy rich. Why do animals store any energy as glycogen? Why not convert all excess fuel into fatty acids? Glycogen is an important fuel reserve for several reasons. The controlled breakdown of glycogen and release of glucose increase the amount of glucose that is available between meals. Hence, glycogen serves as a buffer to maintain blood-glucose levels. Glycogen's role in maintaining blood-glucose levels is especially important because glucose is virtually the only fuel used by the brain, except during prolonged starvation. Moreover, the glucose from glycogen is readily mobilized and is therefore a good source of energy for sudden, strenuous activity. Unlike fatty acids, the released glucose can provide energy in the absence of oxygen and can thus supply energy for anaerobic activity.
Answer:
factor of safety = 0.8
Explanation:
given data
maximum gauge pressure in steel p = 10 MPa
outer diameter do = 200 mm
wall thickness t = 2 mm
ultimate stress of the steel σU = 400 MPa
solution
We check the type of shell that is
so we can see that that is 
so that it mean vessel is a thin shell now we can we get maximum pressure by the maximum tensile stress is
σ = 
.......................1
put here value and we get
σ = 
σ = 500 MPa
so factor of safety will be express as
factor of safety = 
..........2
factor of safety = 
factor of safety = 0.8
