6.Identification of Material ParametersThe principal in-plane stresses and associated strains in a plate of material areσ1= 50 k
si,σ2= 25 ksi,1= 0.00105, and2= 0.000195.(a) This is a plane stress state, meaning the principal stress normal to this plane is zero. Is theprincipal strain3acting normal to this plane also zero? Show why or why not. Draw the 3DMohr’s circle for both stress and strain states.(b) Determine the Modulus of Elasticity,E.(c) Determine Poisson’s ratio,ν.
1 answer:
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Answer:
diameter is 14.83 mm
Explanation:
given data
height = 2 mm
to find out
internal diameter
solution
we consider here material is glass and liquid is water and angle is zero if no capillary rise
we apply here capillary rise formula that is
Capillary rise h = 2T / [ r×ρ×g ] ....................1
put here r is radius and ρ = 1000 kg/m³, T = 72.7 × N/m all value in equation 1
Capillary rise h = 2T / [ r×ρ×g ]
r = 2T / [ h×ρ×g ]
d/2 = 2T / [ h×ρ×g ]
d/2 = 2( 72.7 ×) / [ 2×
×1000×9.8 ]
d = 0.0148336 m
so diameter is 14.83 mm