6.Identification of Material ParametersThe principal in-plane stresses and associated strains in a plate of material areσ1= 50 k
si,σ2= 25 ksi,1= 0.00105, and2= 0.000195.(a) This is a plane stress state, meaning the principal stress normal to this plane is zero. Is theprincipal strain3acting normal to this plane also zero? Show why or why not. Draw the 3DMohr’s circle for both stress and strain states.(b) Determine the Modulus of Elasticity,E.(c) Determine Poisson’s ratio,ν.
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Answer:
The answers are below
Explanation:
a. 180 in^3 to L
1 in³ = 0.0164L
180 in³ =
b. 750 ft-lbf to kJ
1 ft-lbf = 0.00136 kJ
750 ft-lbf =
c. 75.0 hp to kW
1 hp = 0.746 kW
75 hp =
d. 2500.0 lb/h to kg/s
1 lb/h = 0.000126 kg/s
2500.0 lb/h =
e. 120 psia to kPa
1 psia = 6.89 kPa
120 psia =
f. 120 psig to kPa
1 psig = 6.89 kPa
120 psig =
g. 300 ft/min to m/s
1 ft/min = 0.005 m/s
300 ft/min =
h. 125 km/h to miles/h
1 km/h = 0.62 mph
125 km/h =
i) 6000 N to Ibf
1 N = 0.2248 lbf
6000 N =
j. 6000 N to ton
1 N = 0.000102 Ton-force
6000 N =