6.Identification of Material ParametersThe principal in-plane stresses and associated strains in a plate of material areσ1= 50 k
si,σ2= 25 ksi,1= 0.00105, and2= 0.000195.(a) This is a plane stress state, meaning the principal stress normal to this plane is zero. Is theprincipal strain3acting normal to this plane also zero? Show why or why not. Draw the 3DMohr’s circle for both stress and strain states.(b) Determine the Modulus of Elasticity,E.(c) Determine Poisson’s ratio,ν.
1 answer:
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Answer:Counter,
0.799,
1.921
Explanation:
Given data
Since outlet temperature of cold liquid is greater than hot fluid outlet temperature therefore it is counter flow heat exchanger
Equating Heat exchange
=
we can see that heat capacity of hot fluid is minimum
Also from energy balance
=
NTU=1.921