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romanna [79]
3 years ago
5

HELP ME ASAP WITH THIS PLS!!! IM SO CONFUSED

Chemistry
2 answers:
White raven [17]3 years ago
6 0
The answer would be B. If it wasn’t a pure substance the liquid would separate into its components. Like if you put oil and water in a container and shake it up. After some time passes the oil will separate and “float” on top of the water
Ivenika [448]3 years ago
3 0
An Anne jajaja auaiajs jajaja Aisha a jajaja Janak
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When substances react chemically to create a new substance, will that new substance have the same physical and chemical properti
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No it will not have the same chemical properties as the initial substance.

Explanation:

In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants

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Read 2 more answers
At a certain temperature the vapor pressure of pure thiophene is measured to be . Suppose a solution is prepared by mixing of th
Lesechka [4]

Answer:

0.35 atm

Explanation:

It seems the question is incomplete. But an internet search shows me these values for the question:

" At a certain temperature the vapor pressure of pure thiophene (C₄H₄S) is measured to be 0.60 atm. Suppose a solution is prepared by mixing 137. g of thiophene and 111. g of heptane (C₇H₁₆). Calculate the partial pressure of thiophene vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal."

Keep in mind that if the values in your question are different, your answer will be different too. <em>However the methodology will remain the same.</em>

First we <u>calculate the moles of thiophene and heptane</u>, using their molar mass:

  • 137 g thiophene ÷ 84.14 g/mol = 1.63 moles thiophene
  • 111 g heptane ÷ 100 g/mol = 1.11 moles heptane

Total number of moles = 1.63 + 1.11 = 2.74 moles

The<u> mole fraction of thiophene</u> is:

  • 1.63 / 2.74 = 0.59

Finally, the <u>partial pressure of thiophene vapor is</u>:

Partial pressure = Mole Fraction * Vapor pressure of Pure Thiophene

  • Partial Pressure = 0.59 * 0.60 atm
  • Pp = 0.35 atm

3 0
3 years ago
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