According to the cup wall diagrams, why does the double wall vacuum

An interaction of systems allows for the body to warm itself when it is cold. Which processes help the body warm up when it is c

Dmitry_Shevchenko [17]

Answer:

shivering

hair on the body standing up

goosebump forming

Explanation:

The processes that help the body warm-up from the available options include the shivering of the body, formation of goosebumps on the skin, and the standing up of hairs on the body.

When the temperature of the body falls below the setpoint or the environment is cold, a homeostatic response is triggered and a signal is sent from the control center to the muscles of the body. The muscles start shaking in order to generate heat to raise the temperature of the body. At the same time, the tiny muscles at the base of the hairs on the skin contract and pull the hairs erect, causing goosebumps in the process.

6 0

3 years ago

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A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1

Nadya [2.5K]

Answer:

-5,921x10⁶J/mol

Explanation:

Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:

ΔU = q calorimeter + q solution

Where:

q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=6,66°C)

q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=6,66°C)

Replacing:

ΔU = 26920J + 41854J = 68774 J

This energy is per g of n-hexane, now, per mole of n-hexane:

$\frac{68774J}{1gHexane} *\frac{86,1g}{1mol}$ = -5,921x10⁶J/mol

-negative because the energy is produced-

I hope it helps!

5 0

4 years ago

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18. How many moles of atoms are there in each of

Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

= 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of Mg

3.2*10^23=1/6.23*10^23

= 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

= 3.25*10^5/ 207

= 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

= 2.18125*10^-13 moles of oxygen.

3 0

3 years ago

When 280. mL of 1.50 × 10⁻⁴ M hydrochloric acid is added to 135 mL of 1.75 × 10⁻⁴ M Mg(OH)₂, the resulting solution will be?

goldfiish [28.3K]

Answer:

B is the correct answer!

Explanation:

Balanced equation is Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O

HCl is the limiting reactant because it gives the smaller amount of MgCl2 I did the math. This means you will be left with Mg(OH)2 since HCl completely runs out.

If HCl is the limiting reactant, Mg(OH) 2 is the excess reactant.

Mg(OH) 2 is a base, so the solution will be basic.

6 0

3 years ago

What do we call the lines around the nucleus of an atom?

nasty-shy [4]

Explanation:

As you know, electrons are always moving. They spin very quickly around the nucleus of an atom. As the electrons zip around, they can move in any direction, as long as they stay in their shell. Any direction you can imagine — upwards, downwards, or sidewards — electrons can do it. Electrons are constantly spinning in those atomic shells and those shells, or orbitals, are specific distances from the nucleus. If you are an electron in the first shell, you are always closer to the nucleus than the electrons in the second shell.

4 0

3 years ago

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