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2 years ago

Preventive maintenance on a hot water heater includes:

Chemistry

1 answer:

yaroslaw [1]2 years ago

8 0

A water heater can be regularly maintained by flushing it at least two times in a year.

A water heater is a device that is used to heat up water for home use. There are different types of water heaters but they all serve the same purpose at home. In order to maintain maximum efficiency, the water heater must be maintained regularly.

The following are routine maintenance operations on a water heater;

Inspect the heater regularly to ascertain if there are faults.
Flush the heater at least two times each year.
The anode rod should be changed after a couple of years

Learn more about water heater;brainly.com/question/4751630

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What is the solubility of salt in water at room temperature

rewona [7]

<h3><u>Answer;</u></h3>

357 mg/mL

<h3><u>Explanation;</u></h3>

Solubility is defined to be the maximum amount of solute that will dissolve in a given amount of solvent at a specific temperature. The solubility of a salt is one of many physical properties that depend on temperature.
At room temperature 25 °C, the solubility of salt or Sodium Chloride is 357 mg/mL.
For many solutes, increasing the temperature increases the solubility of the solute. The solubility of sodium chloride or table salt is only slightly affected by temperature increase.

5 0

3 years ago

You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles [mol] of 20 grams

vodomira [7]

From the chemical formula the total mass of the compound can be determined. The mass of the 1 mole of the compound is its molar mass. The atom by which the molecule is generated, the mass of these atoms are expressed in terms of amu or atomic unit mass, but after formation of a molecule in a particular ratio the mass of each of the atom becomes the total molecular weight of the generated molecule. In this case the molecule posses three atoms X, Y and Z which are in a ratio of 2:2:7. Thus the chemical formula of the compound can be written as $X_{2}Y_{2}Z_{7}$ .

So the total mass of the compound in amu is {(2×47)+(2×42)+(7×16)} = {94+84+112}=290 amu.

Thus 1 mole of the compound contains 290 amu or 290 g by mass.

Henceforth 20 gram of the compound is equivalent to (20/290) = 0.068 mole.

8 0

3 years ago

What color does red litmus paper turn in an acid base and neutral solution?

quester [9]

<span> red litmus paper turns </span>blue <span>under basic or alkaline conditions, with the color change occurring over the pH range 4.5–8.3 at 25 °C (77 °F). Neutral litmus paper is purple.</span>

6 0

3 years ago

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A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Anna71 [15]

Answer:

31.652g of Na3PO4

Explanation:

We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:

Na3PO4 will dessicate in solution as follow:

Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.

Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e

xM Na3PO4 = (1.10 x 1)/3

xM Na3PO4 = 0.367M

Therefore, the molarity of Na3PO4 is 0.367M.

Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:

Molarity of Na3PO4 = 0.367M

Volume = 525mL = 525/1000 = 0.525L

Mole of Na3PO4 =..?

Molarity = mole /Volume

0.367 = mole /0.525

Cross multiply

Mole of Na3PO4 = 0.367 x 0.525

Mole of Na3PO4 = 0.193 mole.

Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:

Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol

Mole of Na3PO4 = 0.193 mole

Mass of Na3PO4 =.?

Mass = mole x molar mass

Mass of Na3PO4 = 0.193 x 164

Mass of Na3PO4 = 31.652g

Therefore, 31.652g of Na3PO4 is needed to prepare the solution.

6 0

3 years ago

Which group of factors are most important in determining the composition of ocean water? a.)temperature, salinity, and density b

Elis [28]

Temperature, salinity, and density are the group of factors are most important in determining the composition of ocean water.

a.)temperature, salinity, and density

<u>Explanation:</u>

The three fundamental factors that help in determining the composition of ocean water are temperature, salinity, and density. Temperature, saltiness, salinity, and density influence the thickness of seawater.

Enormous water masses of various densities are significant in the layering of the sea water (increasingly thick water sinks). As temperature builds water turns out to be less thick. As saltiness builds water gets denser. The temperature helps in deciding the pace of vanishing of the ocean.

3 0

3 years ago

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