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olga nikolaevna [1]
3 years ago
9

What was the purpose of letting the transformed cells sit in LB for a few minutes before spreading them onto the plates?

Chemistry
1 answer:
MissTica3 years ago
6 0

Answer: D

Explanation:

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Question 23 (5 points)
iren [92.7K]

Answer:

λ = 6.25 × 10⁻¹⁰ m

x-ray

General Formulas and Concepts:

Speed of Light = Wavelength times Frequency

  • c = λν

Explanation:

<u>Step 1: Define</u>

C = 3.0 × 10⁸ m/s

ν  = 4.80 × 10¹⁷ Hz (s⁻¹)

λ = unknown

<u>Step 2: Solve for wavelength</u>

3.0 × 10⁸ m/s = λ(4.80 × 10¹⁷ Hz)

λ = 6.25 × 10⁻¹⁰ m

<u>Step 3: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

6.25 has 3 sig figs. No changes necessary.

<u>Step 4: Identify</u>

6.25 × 10⁻¹⁰ m is in the x-ray spectrum according the the Electromagnetic Spectrum

5 0
3 years ago
Type the correct answer in the box. Express your answer to three significant figures. A balloon is filled with 0.250 mole of air
katrin2010 [14]

Answer:

∴ The absolute pressure of the air in the balloon in kPa = 102.69 kPa.

Explanation:

  • We can solve this problem using the general gas law:

<em>PV = nRT</em>, where,

P is the pressure of the gas <em>(atm)</em>,

V is the volume of the gas in L <em>(V of air = 6.23 L)</em>,

n is the no. of moles of gas <em>(n of air = 0.25 mole)</em>,

R is the general gas constant <em>(R = 0.082 L.atm/mol.K)</em>,

T is the temperature of gas in K <em>(T = 35 °C + 273 = 308 K</em>).

∴ P = nRT / V = (0.25 mole)(0.082 L.atm/mol.K)(308 K) / (6.23 L) = 1.0135 atm.

  • <em>Now, we should convert the pressure from (atm) to (kPa).</em>

1.0 atm → 101.325 kPa,

1.0135 atm → ??? kPa.

∴ The absolute pressure of the air in the balloon in kPa = (101.325 kPa)(1.0135 atm) / (1.0 atm) = 102.69 kPa.

4 0
3 years ago
Read 2 more answers
Goggle meet - brx - tvyn - oge
svp [43]

Answer: um ok...

Explanation: are u saying to join??

5 0
3 years ago
Consider this reaction:
aleksklad [387]

Answer:   0.0345 sec

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[H_3PO_4]^2

k= rate constant = 46.6s^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

for completion of 20 % of reaction

t=\frac{2.303}{46.6}\log\frac{0.660}{\frac{20}{100}\times 0.660}

t=\frac{2.303}{46.6}\log\frac{0.660}{0.132}

t=0.0345sec

The time taken for the concentration of H_3PO_4 to decrease to 20% to its natural value is 0.0345 sec

6 0
3 years ago
Convert 2.1 atm to kPa.
Ira Lisetskai [31]
212.782 kilopascals. Hope this helps :)
3 0
3 years ago
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