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liberstina [14]
3 years ago
9

PLEASE HELP! WILL MARK BRAINLIEST!

Physics
1 answer:
NARA [144]3 years ago
4 0
A. Constructive is correct
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PLEASE HELP , THOSE ARE ALL THE ANSWERS!
insens350 [35]

Answer:

I don't understand

Explanation:

7 0
3 years ago
Read 2 more answers
I am planning to make two dives. The first dive is to 60 feet for 45 minutes, and the second dive is to 60 feet for 35 minutes.
Tpy6a [65]

Answer:

1:04-1:10 hours

Explanation:

You'll need a <em>Recreational dive planner</em> table, I annexed a copy, now you'll follow the next steps:

  1. In the first part of your table, you'll look for the distance row (in feet) of your first dive, for this specific exercise you'll find 60, once you locate it you'll go down that column until you reach the time you'll dive, in this case, 45 (minutes) or the closest value (47).
  2. You'll check and keep the letter in that 47 row (S) for future use.
  3. Now you have to go to the second part of your table and look for the distance column, in feet, of your second dive. We find 60 and then going right in the blue row, we'll look for the time (35) or its closest value (36).
  4. Finally, we have to check the letter for 36 minutes (F) and we'll make it met with the letter S in the first portion of your tables. This will give us an interval of time, 1:04-1:10 in this case.

I hope you find this information useful and interesting! Good luck!

4 0
3 years ago
Between 1911 and 1990, the top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of 1.2 mm/y.T
Anit [1.1K]

Answer:

Angular speed, \omega=6.90\times 10^{-13}\ rad/s

Explanation:

It is given that,    

The top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of, v = 1.2 mm/yr

1\ mm/yr=3.171\times 10^{-11}\ m/s

Velocity, v=3.80\times 10^{-11}\ m/s

Height of the tower, h = 55 m

The height of the tower is equivalent to the radius. Let \omega is the angular speed of the tower’s top about its base. The relation between the angular speed and the angular speed is given by :

v=r\omega

\omega=\dfrac{v}{r}

\omega=\dfrac{3.80\times 10^{-11}\ m/s}{55\ m}

\omega=6.90\times 10^{-13}\ rad/s

So, the average angular speed of the tower’s top about its base is 6.90\times 10^{-13}\ rad/s. Hence, this is the required solution.

6 0
3 years ago
In each cylinder, draw the piston and the gas particles based on the temperature shown.
tangare [24]
I need more information
8 0
2 years ago
Need help on these 2 questions please????? Hurry
fredd [130]

Answer:

Question 1 the anwser is 300 meters.  Question 2 the answer is speed.

is Explanation:

3 0
3 years ago
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