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Answer:
0.055 kg
Explanation:
Given that
Length of the string, l = 5 m
Speed of the wave, v = 30 m/s
Tension on the string, F(t) = 10N
From the formula written in the attachment, we have
v = velocity of the wave, in m/s
F(t) = Tension on the string, in N
U = Mass per length of the string, in kg/m
m = Mass of the string, in kg
l = Length of the string, in m
See attachment for the calculation
Explanation:
The critical velocity is that velocity of liquid flow, up to which its flow is streamlined (laminar)& above which its flow becomes turbulent. It's denoted by Vc & it depends upon: Coefficient of viscosity of liquid (η) Density of liquid. Radius of the tube.
Answer:
Stretch can be obtained using the Elastic potential energy formula.
The expression to find the stretch (x) is 
Explanation:
Given:
Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.
To find: Elongation in the spring (x).
We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).
The formula to find EPE is given as:

Rewriting the above expression in terms of 'x', we get:

Example:
If EPE = 100 J and spring constant, k = 2 N/m.
Elongation or stretch is given as:

Therefore, the stretch in the spring is 10 m.
So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.