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elena55 [62]
4 years ago
6

How many kilojoules in 100 grams

Chemistry
1 answer:
bulgar [2K]4 years ago
4 0
100 grams of what exactly ?
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zimovet [89]

Answer:

Hereeeee

Explanation:

3 0
3 years ago
WILL GIVE BRAINLIEST!
Oliga [24]

Answer:

A

Explanation:

Increasing the the temperature would favour the endothermic reaction which is the forward direction however increasing the pressure would make the reaction try to counteract this change by favouring the reaction that would create more products so the equilibrium will shift left instead of right.

Hope this helps.

4 0
2 years ago
14. How many grams of NaCl are contained in 0.350 kg of a
Lyrx [107]

Answer:

4.87g

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of solution = 0.35kg

Molality = 0.238 m

Mass of NaCl =..?

Step 2:

Determination of the number of mole of NaCl in the solution.

Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:

Molality = mol of solute /mass of solvent (kg)

With the above formula, we calculate the mole of NaCl present in the solution as follow:

Molality = mol of solute /mass of solvent (kg)

0.238 = mol of NaCl /0.35

Cross multiply

mol of NaCl = 0.238 x 0.35

mol of NaCl = 0.0833 mol

Step 3:

Determination of the mass of NaCl in 0.0833 mol of NaCl.

This is illustrated below:

Number of mole NaCl = 0.0833 mol

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl =..?

Mass = number of mole x molar Mass

Mass of NaCl = 0.0833 x 58.5

Mass of NaCl = 4.87g

Therefore, 4.87g of NaCl is contained in the solution.

5 0
4 years ago
. The heat capacity of a bomb calorimeter was determined by burning 6.79 g methane (energy of combustion 802 kJ/mol CH4) in the
kolbaska11 [484]

Answer:

a) The heat capacity of the calorimeter is 31.4 kJ/ºC.

b) The energy of combustion of acetylene in kJ/mol is 1097 kJ/mol.

Explanation:

The heat capacity ( C ) of a substance is <em>the amount of heat required to raise the temperature  of a given quantity of the substance by one degree Celsius</em>. Its units are J/°C. or kJ/ºC.  

If we know the heat capacity and the amount of a substance, then the change in  the sample’s temperature (Δt ) will tell us the amount of heat (<em>q</em>) that has been absorbed  or released in a particular process. One of the equations for calculating the heat change is  given by:

q=C.ΔT

Where ΔT is the temperature change: ΔT= tfinal - tinitial, and C the heat capacity.

In the calorimeter, the heat given off by the sample is absorbed by the water and the bomb. The special design of the calorimeter enables us to assume that no heat (or mass) is lost to the surroundings during the time it takes to make measurements.

Therefore, we can call the bomb and the water in which it is submerged an isolated system. Because no heat enters or leaves the system throughout the process,  the heat change of the system ( q system ) must be zero and we can write:

qsystem = qrxn + qcal

qsystem = 0

where q cal and q rxn are the heat changes for the calorimeter and the reaction, respectively.  Thus, qrxn = -qcal

To calculate <em>q</em>cal , we need to know the heat capacity of the calorimeter ( Ccal ) and the  temperature rise, that is, <em>qcal = Ccal. ΔT</em>

a. The quantity Ccal is calibrated by burning a substance with an accurately known heat  of combustion. In order to do this, we need to convert the molar heat of combustion (expressed in kJ/mol) into heat of combustion (expressed in kJ). For that matter, we transform the 6.79 grams of methane into moles:

1 mol CH₄÷16.04 g CH₄ × 6.79 g CH₄ = 0.423 mol CH₄

And then multiply it by the molar heat of combustion:

802 kJ/mol × 0.423 mol = 339 kJ

Now we know that that the combustion of 6.79 g of methane releases 339 kJ of heat. If the temperature rise is 10.8ºC, then the heat capacity of the calorimeter is given by

Ccal= qcal/ΔT = 339 kJ/10.8ºC = 31.4 kJ/ºC

Once C cal has been determined, the calorimeter can be used to measure the heat of  combustion of other substances.  Note that although the combustion reaction is exothermic, q cal is a positive quantity because it represents the heat absorbed by the calorimeter.

b. The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with the same equation, and assuming no heat is lost to  the surroundings, we write

qcal=Ccal.ΔT= 31.4 kJ/°C × 16.9 °C = 531kJ

Now that we have the heat of combustion, we need to calculate the molar heat.   Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -531 kJ.

This is the heat released by the combustion of 12.6 g of acetylene ; therefore, we can write  the conversion factor as 531 kJ÷12.6 g

The molar mass of acetylene is 26.04 g, so the heat of combustion of 1 mole of acetylene is

 molar heat of combustion= -531 kJ÷12.6 g × 26.04 g÷ 1 mol= 1097 kJ/mol

Therefore, the energy of combustion of acetylene in kJ/mol is 1097 kJ/mol.

7 0
4 years ago
If a chemical is oxidized it is also known as the
RUDIKE [14]

Answer:

D.) reducing agent

Explanation:

Oxidized chemicals gain electrons. In order to gain these electrons, another chemical must lose electrons. So, the chemical (which will be oxidized) acts as a reducing agent, causing the other chemical to be reduced and lose electrons.

4 0
2 years ago
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