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3 years ago

When air cools, it holds _____ water than when it is warmer.

Physics

2 answers:

Doss [256]3 years ago

8 0

The answer is A. less. Hope it helps

Blizzard [7]3 years ago

6 0

It holds A. Less water than when it is warmer.

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Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th

irinina [24]

I'm not quite sure what happens to Fay so I didn't finish but hope it helps

5 0

3 years ago

Read 2 more answers

4. A stone is dropped from the fifth floor of a building from a height 14 m. How long would it take

aleksklad [387]

Answer:

1.690308509s

Explanation:

v²=u²+2as

v²=0²+2(9.8)(14)

v²=274.4

∴v=16.56502339m/s

v=u+at

16.56502339=0+9.8t

∴t=1.690308509s

6 0

3 years ago

The compound limestone (which is mined in Crossville) is chemically

Salsk061 [2.6K]

Answer:

True

Explanation:

Limestone is a carbonate chemical sedimentary rock often chemically called calcium carbonate.

The mineral calcium carbonate makes up the framework of this rock that has become the staple material used for cement production.

Chemically, the formula is given as CaCO₃. The rock accumulates from the a rich deposit of calcite, which is the mineral that is made up of calcium carbonate to form the limestone.

CaCO₃ - Calcite - Limestone

compound mineral rock

Limestone is a rock and the compound it is made up of is calcium carbonate. In some cases, a Ca-Mg carbonate occurs with limestone and it is called a dolomite.

5 0

4 years ago

A book is dropped from a window. It takes 5 seconds to reach the ground. What is its velocity after 2 seconds? What’s the veloci

ira [324]

Answer:

Explanation:

Initial velocity is 0. In the equation v = v0+at where v0 is the initial velocity of 0, we only have to fill in -9.8 for a and 2 for t to get the velocity after 2 seconds -19.6 m/s; after 5 seconds, when it hits the ground, a = -9.8 and t = 5 to give a velocity of -49 m/s. Gravity pulls down everything at the same rate, it doesn't matter whether we drop a feather or an elephant from the window!

3 0

3 years ago

Two identical positive charges exert a repulsive force of 6.2 × 10−9 n when separated by a distance 3.7 × 10−10 m. calculate the

In-s [12.5K]

The electrostatic force between two charges is given by
$F=k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is their separation

In this problem, the two charges are identical, so we can call them q1=q2=q, and the formula becomes
$F=k \frac{q^2}{r^2}$

Since we know the magnitude of the force and the separation between the two charges, we can re-arrange the equation to find the value of each charge:
$q= \sqrt{ \frac{Fr^2}{k} } = \sqrt{ \frac{(6.2 \cdot 10^{-9} N)(3.7 \cdot 10^{-10}m)^2}{8.99 \cdot 10^9 Nm^2C^{-2}} }=3.07 \cdot 10^{-19} C$

5 0

3 years ago