Answer: 6117.58 J
Explanation:
We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.
In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.
Plugging all this in we get
W=225*30*cos(25)=6117.58 J
Wavelength times frequency = speed of light
7.5E14 x wavelength = 300,000 m/s
Wavelength in meters = 300,000 divided by 7.5E14
It works by you putting leverage on one side makes more force go to the other side so if you put a crowbar in between a door and you push on one side the other will push the opposite side with more force<span />
C. I did it bit i forgot how I did it
Answer:
= 4.86 s
= 1.98 s
Explanation:
<u><em>Given:</em></u>
Length = l = 1 m
Acceleration due to gravity of moon =
= 1.67 m/s²
Acceleration due to gravity of Earth =
= 10 m/s²
<u><em>Required:</em></u>
Time period = T = ?
<u><em>Formula:</em></u>
T = 2π ![\sqrt{\frac{l}{g} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%20%7D)
<u><em>Solution:</em></u>
<u>For moon</u>
<em>Putting the givens,</em>
T = 2(3.14) ![\sqrt{\frac{1}{1.67} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B1%7D%7B1.67%7D%20%7D)
T = 6.3 ![\sqrt{0.6}](https://tex.z-dn.net/?f=%5Csqrt%7B0.6%7D)
T = 6.3 × 0.77
T = 4.86 sec
<u>For Earth,</u>
<em>Putting the givens</em>
T = 2π ![\sqrt{\frac{1}{10} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B1%7D%7B10%7D%20%7D)
T = 2(3.14) ![\sqrt{0.1}](https://tex.z-dn.net/?f=%5Csqrt%7B0.1%7D)
T = 6.3 × 0.32
T = 1.98 sec