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Bogdan [553]
3 years ago
7

Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan

ced reaction (Ks = 1.4x10): Ag2SO4) = 2 Ag (aq) + S0 + (aq) i) Calculate the molar solubility (S) of Ag2SO4. [15 marks] ii) Calculate the solubility (S') of Ag2SO4 in grams per liter.
Chemistry
1 answer:
natka813 [3]3 years ago
4 0

Answer:

a) S = 0.0152 mol/L

b) S' = 4.734 g/L

Explanation:

  • Ag2SO4 ↔ 2Ag+  +  SO42-

           S                2S            S...............in the equilibrium

  • Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]

a) molar solubility:

⇒ Ksp = ( 2S) ² * S = 1.4 E-5

⇒ 4S² * S = 1.4 E-5

⇒ S = ∛ ( 1.4 E-5 / 4 )

⇒ S = 0.0152 mol/L

b) solubility ( S' ) in grams per liter:

∴ Mw Ag2SO4 = 311.799 g/mol

⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

⇒ S' = 4.734 g/L

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3 years ago
if i add water to 100 mL of a 0.75 M NaOH solution un til the final volume is 165mL what will the molarity of the diluted soluti
ehidna [41]
Answer is: <span>the molarity of the diluted solution 0,454 M.
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kompoz [17]

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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\text{Number of moles}=\frac{0.610g}{78g/mol}

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The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

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