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Leya [2.2K]
3 years ago
13

Compared with a mole of oxygen-16, a mole of sulfur-32 contains: A. twice as many atoms B. half as many atoms C. an equal number

of atoms D. 8 times as many atoms Explain why: I'll be rewarding 100 points. Please answer and please explain Why.
Chemistry
1 answer:
trasher [3.6K]3 years ago
7 0

Given :

Compared with a mole of oxygen-16, a mole of sulfur-32 contains:

A. twice as many atoms .

B. half as many atoms .

C. an equal number of atoms .

D. 8 times as many atoms .

To Find :

The correct option .

Solution :

One mole of atoms of oxygen-16 has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02\times 10^{23} atoms of oxygen.

Same, one mole of sulfur-32 has 32 g mass , and contains same 6.02\times 10^{23} atoms of sulfur .

So , both have equal number of atoms .

Therefore , option C. is correct .

Hence , this is the required solution .

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__Ca +__ H20- _Ca(OH)2 + _H2
astra-53 [7]

Answer: 44

Explanation: Because its easy

7 0
2 years ago
The element lanthanum has two stable isotopes, lanthanum-138 with an atomic mass of 137.9 AMU and lanthanum-139 with an atomic m
dmitriy555 [2]

Answer:

A. there is an isotope of lanthanum with an atomic mass of 138.9

Explanation:

By knowing the different atomic masses of both Lanthanum atoms, we can not tell anything about their occurence in nature. Therefore, all the last three options are incorrect. Because, the atomic mass does not tell anything about the availability or natural abundance of an element.

Now, the isotopes of an element are those elements, which have same number of electrons and protons as the original element, but different number of neutrons. Therefore, they have same atomic number but, different atomic weight or atomic masses.

Hence, by looking at an elements having same atomic number, but different atomic masses, we can identify them as isotopes.

Thus, the correct option is:

<u>A. there is an isotope of lanthanum with an atomic mass of 138.9.</u>

7 0
3 years ago
Which compound is an exception to the octet rule? H20 HCI CCI4 CIF3
Reika [66]

Answer:

clf3

Explanation:

it occupied more than 8 valence electrons

8 0
3 years ago
the volume of gas in a container was originally 3.24L, while at standard pressure 1.00 atm. what will the volume be if the press
Simora [160]
Hello!

To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:

P1*V1=P2*V2 \\ \\ V2= \frac{P1*V1}{P2}= \frac{3,24 L * 1 atm}{1,20 atm}= 2,7 L

So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases

Have a nice day!
8 0
3 years ago
Chemistry check please... Thank you!
I am Lyosha [343]
1) We apply the ideal gas equation:
PV = nRT
n = (21300 x 3/1000) / (8.314 x 323)
n = 0.024
Your answer is correct.

2) Total pressure = Partial pressure of Hydrogen + Partial pressure of water
134.7  = 122.4 + Pw
Pw = 12.3 kPa
Your answer is correct

3) The molar fraction, volume fraction and pressure fraction of gasses are the same thing.
Thus, percentage pressure of Oxygen = 10%
Pressure of Oxygen = 2.04 x 10⁴ x 0.1
= 2.04 x 10³ kPa
Your answer is correct

Well done!
3 0
3 years ago
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