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Alexxx [7]
3 years ago
15

What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin

g molarity and show your work for each step in the calculation.
Chemistry
1 answer:
beks73 [17]3 years ago
6 0

Answer:

\boxed{\text{2 mol/L}}

Step-by-step explanation:

c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }

Data:

n = 5 mol

V = 2.5 L

Calculation:

c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}

The molar concentration of the solution is \boxed{\textbf{2 mol/L}}.

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A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
3 years ago
A lithium atom has three protons, three neutrons, and three electrons. what is the overall charge on this atom? a–3 b 0 c 1 d 3
fredd [130]

  Lithium atomic number = 3

  Li atom has 3 protons,3 electrons.Then it has no charge.

So the charge of Li atom here is zero.

<u>Option b: 0 is the right answer.</u>

5 0
3 years ago
Read 2 more answers
What happens to glucose in the Calvin cycle? <br><br> Plz help
Leona [35]

The reactions of the Calvin cycle add carbon from carbon dioxide in the atmosphere to a five-carbon molecule known as RuBP. These reactions use chemical energy that were produced in the light reactions, from NADPH and ATP. The final product of the Calvin cycle is glucose.

7 0
3 years ago
You need 455 ml of a 75% alcohol solution. on hand, you have a 25% alcohol mixture. you also have a 90% alcohol mixture. how muc
marishachu [46]
X ml - <span>25% alcohol mixture
y ml - </span><span>90% alcohol mixture

x+y = 455 

0.25x ml alcohol in </span>x ml of  25% alcohol mixture
0.9y ml alcohol in y ml of  90% alcohol mixture
0.75*455= 341.25 ml alcohol in 455 ml of  75% alcohol mixture

0.25x+0.9y=341.25 

System of equations:

x+y = 455 /*(-0.25) ------> -0.25x-0.25y = -0.25*455 
0.25x+0.9y=341.25

-0.25x-0.25y=-113.75
0.25x+0.9y=341.25    Add both equations

0.25x+0.9y-0.25x-0.25y=341.25-113.75
0.65y =227.5
y=227.5/0.65 = 350 ml  of  90% alcohol mixture

x+y=455
x+355=455
x=100 ml of  25% alcohol mixture

8 0
3 years ago
Pis
loris [4]

Answer:

5.00×10-19 J

Explanation:

E = hv

but v = c ÷ wavelength

E = (6.626×10-34) × ((3×10^8)÷(398×10-9))

= 4.9945×10-19

≈5.00×10-19

Hope this helps

8 0
2 years ago
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