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Taya2010 [7]
3 years ago
15

Lead-214 has a half-life of 43.5 seconds. What percent of a sample of this isotope would be left after a time equivalent to 7 ha

lf-lives?
Physics
1 answer:
pshichka [43]3 years ago
6 0

Answer:

Explanation:

Lead has an half life of 43.5 seconds

The radioactive decay law says

N(t) = No•2^(-t / t½)

Hence, the percent of a sample of the Lead-214 isotope that decay after a time equivalent to 7 half-lives

​N(t) = No•2^(-t / t½)

N(t) / No = 2^(-t / t½)

N(t) / No = 2^-7

N(t) / No = 7.81 × 10^-3

To percentage

N(t) / No = 7.81 × 10^-3 × 100

N(t) / No = 0.781 %

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4 years ago
A baseball player hits a ball with a bat. At one moment the force exerted by the bat on the ball is 18,000 N. At that same momen
11111nata11111 [884]

Answer:

Less than 18000N

Explanation:

Given

Force\ Exerted = 18000N

This question will be answered using Newton's third law.

Understanding this law, it implies that reaction force is equal and opposite to the force exerted.

This implies that;

If the force exerted on the ball is 18000N

the force exerted is -18000N

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5 0
3 years ago
Two charged particles are accelerated through a uniform electric field and zero magnetic field, then enter a region with zero el
Mrac [35]

Answer:

Explanation:

In magnetic field , charged particle will have circular path . Let the radius of their circular path be r₁ and r₂ . Let their velocity at the time of entering magnetic field be v₁ and v₂ .

The velocity with which they will come out of electric field can be measured from following equation

Eq = 1/2 m v²  , E is electric field , q is charge on the particle , m is mass and v is velocity .

v² = 2Eq / m

radius of circular path can be measured by the following expression

m v² / r = Bqv

2Eq / r = Bqv

r = 2Eq / Bqv

= 2E / Bv

r² = 4E² / B²v²

= 4E²m / B²x 2Eq

since E , B and q are constant

r² = K . m

r₂² / r₁² = m₂ / m₁

1.5²

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6 0
3 years ago
Which is best supported by the data in the chart?
bija089 [108]

Answer:

Option C: Current X has a lower potential difference than Current Y.

Explanation:

The chart above only shows the potential difference of difference current.

A careful observation of the chart shows that Current X has a lower potential difference than Current Y.

7 0
3 years ago
A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?
Blababa [14]

Answer:

Explanation:

V^2=V^2_o+2a(x_f-x_i)

28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2

5 0
3 years ago
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