Question

at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure of 0.612 atm and a temperature of 28.0c

Answer 1

Answer:

initial temperature=$-3.31^{\circ}C$

Explanation:

Assuming that the given follows the ideal gas nature;

$P_1=0.723atm$

$V_1=13.5L$

$T_1=?$

$P_2=0.612atm$

$V_2=17.8L$

$T_2=28 ^{\circ}C =273+28K=301K$

mole of gass will remain same at any emperature:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

putting all the value we get:

$T_2 =269.7K =-3.31 ^{\circ} C$

initial temperature=$-3.31^{\circ}C$