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Marianna [84]
3 years ago
9

The image shows the path of a ball from the time it’s thrown to the time it lands on the ground. Determine the kind of energy th

e ball has at each position. (PE stands for gravitational potential energy, and KE stands for kinetic energy.)
PE
neither
PE and KE

Physics
1 answer:
LenaWriter [7]3 years ago
4 0

At Position 1: The ball has both PE and KE. (The ball is at a height from ground and velocity is given to the ball)

At Position 2: The ball has both PE and KE. (The ball is at a height from ground and velocity is also there.

At Position 3: The ball has both PE and KE. (The ball is at a height from ground and velocity is also there.)

At position 4: The ball has only PE. (The ball is at a height from ground and velocity is zero.)

At position 5: The ball has both PE and KE. (The ball is at a height from ground and velocity is also there.)

At position 6: The ball has both PE and KE. (The ball is at a height from ground and velocity is also there.)

At position 7: The ball has only KE (Just before hitting the ground). After landing the ball have neither of the energy.

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What does the slope of a velocity versus time graph represent?​
liberstina [14]
The slope represents the acceleration
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What do the mean by cubic expansivity​
olganol [36]
A real cubic expansivity is an increase in the volume of a liquid per unit volume per degree rise in temperature when heated in an inexpansible vessel.
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Read 2 more answers
A bus leaves at 9 am with a group of tourists. They travel 350 km before they stop for lunch. Then they travel an additional 250
Anettt [7]

Average speed = Distance traveled / time taken

In this case Time taken = Difference in hours between 3 PM and 9 AM

                                        = 6 hours

Total distance traveled = 350 km + 250 km

                                       = 600 kilometers

So average speed = 600/6 = 100 km/hr

Average speed of bus = 27.78 m/s

So the bus's average speed = 27.78 m/s or 100 km/hr.

8 0
3 years ago
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car ent
Paha777 [63]

Answer:

0.8712 m/s²

Explanation:

We are given;

Velocity of first car; v1 = 33 m/s

Distance; d = 2.5 km = 2500 m

Acceleration of first car; a1 = 0 m/s² (constant acceleration)

Velocity of second car; v2 = 0 m/s (since the second car starts from rest)

From Newton's equation of motion, we know that;

d = ut + ½at²

Thus,for first car, we have;

d = v1•t + ½(a1)t²

Plugging in the relevant values, we have;

d = 33t + 0

d = 33t

For second car, we have;

d = v2•t + ½(a2)•t²

Plugging in the relevant values, we have;

d = 0 + ½(a2)t²

d = ½(a2)t²

Since they meet at the next exit, then;

33t = ½(a2)t²

simplifying to get;

33 = ½(a2)t

Now, we also know that;

t = distance/speed = d/v1 = 2500/33

Thus;

33 = ½ × (a2) × (2500/33)

Rearranging, we have;

a2 = (33 × 33 × 2)/2500

a2 = 0.8712 m/s²

3 0
3 years ago
a large truck has a mass of 20000kg. it is traveling at 28m/s along a staright road . calculate the kinetic energy ​
Semmy [17]

Answer:

The answer is

<h2>7,840,000 J</h2>

Explanation:

The kinetic energy KE of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}  \\

where

m is the mass

v is the velocity

From the question

m = 20000kg

v = 28 m/s

It's kinetic energy is

KE =  \frac{1}{2}  \times 20000 \times  {28}^{2}  \\  = 10000 \times 784

We have the final answer as

<h3>7,840,000 J</h3>

Hope this helps you

3 0
3 years ago
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