Answer:
Given:
radius of the coil, R = 6 cm = 0.06 m
current in the coil, I = 2.65 A
Magnetic field at the center, B =
Solution:
To find the number of turns, N, we use the given formula:
Therefore,
N = 22.74 = 23 turns (approx)
The image shows the path of a ball from the time it’s thrown to the time it lands on the ground. Determine the kind of energy th
e ball has at each position. (PE stands for gravitational potential energy, and KE stands for kinetic energy.)
PE
neither
PE and KE
PE
neither
PE and KE
1 answer:
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Answer:
(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%
Explanation:
Using the formula that relate heat and work from the thermodynamic theory as: solving to Q_out we get:
this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us:
where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get: