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Annette [7]
3 years ago
14

The relationship between the weight and mass of an object is given by the formula, W=mg, where W=weight, m= mass and g= the stre

ngth of gravity. On the moon, the strength of gravity is 1.6N/kg. A 22-kilogram rock on the moon would weigh ?
Physics
1 answer:
Shkiper50 [21]3 years ago
3 0
Yaaaaaaaaaaaaasssssssssss
You might be interested in
PLEASE HELP ME WITH THIS ONE QUESTION
Marizza181 [45]

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

<em>Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope</em>

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

<h3>c) 2.02 x 10^16 nuclei</h3>
7 0
2 years ago
Which of the following causes an object to move in a curved path?
Brrunno [24]

Answer:

A. centripetaal force

3 0
3 years ago
Read 2 more answers
Calculate the amount of heat (in kj) required to raise the temperature of a 79.0 g sample of ethanol from 298.0 k to 385.0 k. th
earnstyle [38]
We are given with the specific heat capacity of ethanol, the mass of the sample and the temperature change to determine the total amount of heat to raise the temperature. The formula to be followed is H = mCpΔT. Upon subsituting, H = 79 g * 2.42 J/gC *(385-298)C = 16.63 kJ 
7 0
3 years ago
Which of the following is an example of a physical change?
Stels [109]

Answer:

1 question is- I believe 4. Melting Question 2 is Density

Explanation:

THOUGHT ABOUT IT!!!

7 0
3 years ago
An auditorium measures 40.0 m 3 20.0 m 3 12.0 m. The density of air is 1.20 kg/m3. What are (a) the volume of the room in cubic
Burka [1]

We use the formula,

m = V\rho

Here, m is the mass, V is the volume and  \rho density

Also

V = l w h

Here l is length, w is width and h is height.

(a) The volume of the room,

V=40.0 \ m \times 3 20.0 \ m \times 3 12.0\ m = 3.99 \times 10^{6} m^3

The volume of the room in cubic feet,

V = 3.99 \times 10^{6} m^3 \times(\frac{3.281 \ ft}{m} )^3 = 4.3 \times 10^7 \ ft^3

(b) Now the mass of the air in room,

m= (3.99 \times 10^{6} \ m^3) (1.20 \ kg/m^3) = 4.8 \times 10^6 kg.

Therefore, the weight of the air in room,

W = mg= 4.8 \times 10^6 kg \times 9.8 m/s^2 = 46.9 \times 10^6 \ N \\\\ W = 4.69 \times 10^7 \ N.

The weight of air in the room in pounds,

W = 4.69 \times 10^7 \ N ( \frac{1 \ lb}{4.448 \ N} ) = 1.1 \times 10^7 \ lb


3 0
3 years ago
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