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3 years ago

PLEASE HELP ME WITH THIS ONE QUESTION

Physics

1 answer:

Marizza181 [45]3 years ago

7 0

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

<h3>c) 2.02 x 10^16 nuclei</h3>

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Zanzabum

Answer:

$y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$

Explanation:

given,

wavelength, λ = 50 cm

speed, v = 4 m/s

Amplitude, A = 5 cm

general equation of the wave along x- axis

$y = A sin(2\pi(\dfrac{x}{\lambda})\pm \nu t)$

sign is positive when wave is traveling in negative direction

now,

$\nu = \dfrac{v}{\lambda}$

$\nu = \dfrac{4}{0.5}$

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inserting all the values

$y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$

Hence, the y-equation of wave is equal to $y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$

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3 years ago

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4 years ago

PLEASE HELP, THANK YOU!.. :)

Firlakuza [10]

Answer:

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3 years ago

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3 years ago

The graph below represents the relationship between the force exerted on an elevator and the distance the elevator is lifted.

Stella [2.4K]

I have three problems with this question.

#1). If you copied the question exactly the way it's written,
then the question is written very badly. The wording is
misleading, and the more you try to think about it and
puzzle it out, the more it'll damage your understanding
of Physics.

There is no relationship between the force exerted on an
elevator and the distance the elevator is lifted.

-- If the force is anything more than the weight of the elevator ...
even one ounce more ... then it'll lift the elevator as high as
you want.

-- If the force is anything less than the weight of the elevator ...
even one ounce less, then that elevator is headed for the bottom.

#2). You didn't post any graph below, so if we need the graph
to answer the question, then we can't answer the question.

#3). I guess that's OK, because you didn't ask any question.

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3 years ago