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vlada-n [284]
3 years ago
6

A wave travels at 330m/s^-1. the wavelength is found to be 2.4m.

Physics
1 answer:
sveta [45]3 years ago
7 0

Answer: frequency 137.5

Time period 0.01sec

Explanation:

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Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Arada [10]

Answer:

b. a large elliptical galaxy

Explanation:

In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.

The stars orbit in a messy way which made to believe that they form from the merger of galaxies.

They are also really massive (around 10^{4} solar masses).

The most massive and luminous can be found in the center of cluster of galaxies.  

4 0
3 years ago
An athlete is running a 5-km race at an average speed of 8 km/h. She has to stop to tie her shoe. After tying her shoe, she cont
Ray Of Light [21]
The total time she took to complete the race increased
5 0
3 years ago
What percentage of the takeoff velocity did the plane gain when it reached the midpoint of the runway? a plane accelerates from
ElenaW [278]
When is at the end of the runway the velocity of the plane is given by the equation vf^{2}=0+2*a*s    where s=1800 m is the runway length. Thus
vf^{2}=2*5*1800=18000 (m/s)^{2}      
vf =134.164 (m/s)  

At half runway the velocity of the plane is
v^{2}=2*5* \frac{1800}{2}=9000 ( \frac{m}{s} )^{2}
 
v= \sqrt{9000}=94.87 ( \frac{m}{s})

Therefore at midpoint of runway the percentage of takeoff velocity is
‰P= \frac{v}{vf}=  \frac{94.87}{134.164}=0.707
6 0
3 years ago
Which of the following are vector quantities?
pshichka [43]

Answer:

Vector Quantity: A physical quantity is said to be a vector quantity when it has both magnitude and direction. The scalar quantities are distance, mass, time, volume, density, speed, temperature, and energy, The vector quantities are weight, velocity, acceleration, and force.

Explanation:

Mark me brainleist PLZZZZ

8 0
3 years ago
Read 2 more answers
You stand on a frictionless platform that is rotating with an angular speed of 5.1 rev/s. Your arms are outstretched, and you ho
timurjin [86]

Answer:

\omega'=19.419\ rev.s^{-1}

Explanation:

Given:

angular speed of rotation of friction-less platform, \omega=5.1\ rev.s^{-1}

moment of inertia with extended weight, I=9.9\ kg.m^2

moment of inertia with contracted weight, I'=2.6\ kg.m^2

<u>Now we use the law of conservation of angular momentum:</u>

I.\omega=I'.\omega'

9.9\times 5.1=2.6\times \omega'

\omega'=19.419\ rev.s^{-1}

The angular speed becomes faster as the mass is contracted radially near to the axis of rotation.

5 0
3 years ago
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