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uranmaximum [27]
3 years ago
11

If a star with an absolute magnitude of -5 has an apparent magnitude of +5 ,then its distance is

Physics
1 answer:
klio [65]3 years ago
6 0
You asked a question.  I'm about to answer it. 
Sadly, I can almost guarantee that you won't understand the solution. 
This realization grieves me, but there is little I can do to change it. 
My explanation will be the best of which I'm capable.


Here are the Physics facts I'll use in the solution:

-- "Apparent magnitude" means how bright the star appears to us.

-- "Absolute magnitude" means the how bright the star WOULD appear
if it were located 32.6 light years from us (10 parsecs).

-- A change of 5 magnitudes means a 100 times change in brightness,
so each magnitude means brightness is multiplied or divided by  ⁵√100 .
That's about  2.512... .  

-- Increasing magnitude means dimmer.
Decreasing magnitude means brighter.
+5 is 10 magnitudes dimmer than -5 .

-- Apparent brightness is inversely proportional to the square
of the distance from the source (just like gravity, sound, and
the force between charges).

That's all the Physics.  The rest of the solution is just arithmetic.
____________________________________________________

-- The star in the question would appear M(-5) at a distance of
32.6 light years. 

-- It actually appears as a M(+5).  That's 10 magnitudes dimmer than M(-5),
because of being farther away than 32.6 light years.

-- 10 magnitudes dimmer is ( ⁵√100)⁻¹⁰ = (100)^(-2) .

-- But brightness varies as the inverse square of distance,
so that exponent is (negative double) the ratio of the distances,
and the actual distance to the star is

(32.6) · (100)^(1) light years

= (32.6) · (100) light years

=  approx.  3,260 light years .   (roughly 1,000 parsecs)


I'll have to confess that I haven't done one of these calculations
in over 50 years, and I'm not really that confident in my result.
If somebody's health or safety depended on it, or the success of
a space mission, then I'd be strongly recommending that you get
a second opinion.
But, quite frankly, I do feel that mine is worth the 5 points.
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<h3><u>Answer;</u></h3>

Satellite

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3 0
3 years ago
Read 2 more answers
You are on an interstellar mission from Earth to the distant star Sirius, which is 8.7 light years away. Your spaceship can trav
gulaghasi [49]

Answer:

(a). 12.43 years.

(b). 3.89 × 10^ -9 kg.

Explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question;

=> " mission from Earth to the distant star Sirius has a light year = 8.7 light years away. "

=> "The spaceship can travel with 70% the speed of light"

=> " The spaceship's cylinder shape has a diameter of 6 meters at the front surface and a length of 25 meters. "

=> density = 1 hydrogen atom/m^3.

Step one: convert light year to metres.

J = 8.7 × 9.461 × 10^15 = 8.23 × 10^16 m.

Step two: convert percentage speed of light to metre per seconds;

70% = 70/100 = 0.7.

U = 0.7 × speed of light = 0.7 × 3.0 × 10^8 = 2.1 × 10^8 m/s.

(a).

Step three: determine the time taken(convert to years);

J / U = time taken; = 8.23 × 10^16 m/ 2.1 × 10^8 m/s = 12.43 years.

(b). The mass of interstellar gas that collides with your spaceship during the mission;

Volume= {(6m)^2 × 22/7}/ 4 × ( 8.23 × 10^16 m). = 2.33 × 10^18 m^3..

Density = mass/volume .

Mass= [24 × 365 × 3600 × 3 × 10^8 × 8.7 × 1.673 × 10^-27 × 6^2 × 22/7]/4 = 3.89 × 10^ -9 kg.

3 0
4 years ago
How is the strength of an electromagnet affected by the number of turns<br> of wire in a coil?<br> e
Anastasy [175]

Answer:I don't know

Explanation:

3 0
3 years ago
Need help with these physic questions!
gtnhenbr [62]

Explanation:

4.

Given: Δd = 4 + 2 + 1 = 7km, Δt = 32 + 22 + 16 = 70mins

Required: V

Equation: V = Δd/Δt

Solution: V = 7/70

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6 0
3 years ago
Determine the electrical force of attraction between two balloons with separate charges of +3.5 × 10-8 C and -2.9 × 10-8 C when
kenny6666 [7]

Answer:

The electrical force of attraction between the balloons is 2.16\times 10^{-5}\ N.

Explanation:

Given that,

Charge 1, q_1=+3.5\times 10^{-8}\ C

Charge 2, q_2=-2.9\times 10^{-8}\ C

Distance between the charges, d = 0.65 m

We need to find the electrical force of attraction between two balloons. It is given by the formula as :

F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{3.5\times 10^{-8}\times 2.9\times 10^{-8}}{(0.65)^2}\\\\F=2.16\times 10^{-5}\ N

So, the electrical force of attraction between the balloons is 2.16\times 10^{-5}\ N. Hence, this is the required solution.

3 0
3 years ago
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