Answer:
0.0308 mol
Explanation:
In order to convert from grams of any given substance to moles, we need to use its molar mass:
- Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2
- Molar mass of KAI(SO₂)₂ = 194 g/mol
Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:
- 5.98 g ÷ 194 g/mol = 0.0308 mol
Answer:
dG will be the same -20 kcal/mol
Explanation:
The dG can be expressed in terms of the G(products) - G(reactants). If the amount of enzyme is doubled the Gibbs energy of the reactants and products will be the same, so the substraction dG has the same value
A good example of intrusive igneous rock is granite<span> . Extrusive igneous rocks form when the </span>magma<span> or molten rock pours out onto the earth's surface or erupts at the earth's surface from a volcano . Extrusive rocks are also called volcanic rocks.</span>Basalt<span> , formed from hardened </span>lava<span> , is the most common extrusive rock</span>
I’m not sure what you’re asking but- halogens are among the most active nonmetals due to their electron configuration and number of valence electrons.
Both of these questions can be solved using the equation M1V1 = M2V2, where M is concentration anf V is volume.
For the first case, M2 = 0.2 mol/L, M1 = 3 mol/L, and V2 = 250mL. So now you want V1. Solving for V1, V1 = (M2 / M1)V2 =
(0.2 / 3)(250) = 16.7 mL. So what that means is that you need 16.7 mL of 3M HCl, and the rest of the 250 mL (which would be 250 - 16.7 = 233.3 mL) would be water, with which you're diluting the HCl.
Same principle for the second problem, except now we have percentages and not mol/L. You can treat the percentages as concentrations. Since you're starting with pure isopropyl alcohol, M1 = 100%. You want a final volume of 500 mL and a final concentration of 70%. To find the volume of isopropyl alcohol you need to start with, solve for V1. So V1 = (M2 / M1)V2 = (70 / 100)(500) = 350 mL. So you need 350 mL of isopropyl alcohol and the rest of the 500 mL (that is, 150 mL) you can fill with water.
