Answer:
2.2 m/s^2
Explanation:
Acceleration = Force / Mass
= 7.92 / 3.6 = 2.2m/s^2
Hope this help you :3
Answer:
Yes
Explanation:
Because if you push it, the skateboard has kinetic/potential energy.
Answer:
7229 N
Explanation:
The gravitational force between the Death Star and the Millenium Falcon is given by:
![F=G\frac{mM}{R^2}](https://tex.z-dn.net/?f=F%3DG%5Cfrac%7BmM%7D%7BR%5E2%7D)
where
is the gravitational constant
is the mass of the Death Star
is the mass of the Millennium Falcon
is the radius of the Death Star
Substituting numbers into the equation, we find the force
![F=(6.67\cdot 10^{-11})\frac{(1.36\cdot 10^6 kg)(5.1\cdot 10^{17} kg)}{(80,000 m)^2}=7229 N](https://tex.z-dn.net/?f=F%3D%286.67%5Ccdot%2010%5E%7B-11%7D%29%5Cfrac%7B%281.36%5Ccdot%2010%5E6%20kg%29%285.1%5Ccdot%2010%5E%7B17%7D%20kg%29%7D%7B%2880%2C000%20m%29%5E2%7D%3D7229%20N)
Hello!
First one we can use that PE=mgh so we have
4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m
Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have
g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2
Hope this helps. Any questions please ask. Thank you.
The acceleration of the runner in the given time is 2.06m/s².
Given the data in the question;
Since the runner begins from rest,
- Initial velocity;
![u = 0](https://tex.z-dn.net/?f=u%20%3D%200)
- Final velocity;
![v = 13.4m/s](https://tex.z-dn.net/?f=v%20%3D%2013.4m%2Fs)
- Time elapsed;
![t = 6.5s](https://tex.z-dn.net/?f=t%20%3D%206.5s)
Acceleration of the runner; ![a = \ ?](https://tex.z-dn.net/?f=a%20%3D%20%5C%20%3F)
<h3>Velocity and Acceleration</h3>
Velocity is the speed at which an object moves in a particular direction.
Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion
![v = u + at](https://tex.z-dn.net/?f=v%20%3D%20u%20%2B%20at)
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
To determine the acceleration of the runner, we substitute our given values into the equation above.
![v = u + at\\\\13.4m/s = 0 + (a * 6.5s)\\\\13.4m/s = a * 6.5s\\\\a = \frac{13.4m/s}{6.5s}\\ \\a = 2.06m/s^2](https://tex.z-dn.net/?f=v%20%3D%20u%20%2B%20at%5C%5C%5C%5C13.4m%2Fs%20%3D%200%20%2B%20%28a%20%2A%206.5s%29%5C%5C%5C%5C13.4m%2Fs%20%3D%20a%20%2A%206.5s%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B13.4m%2Fs%7D%7B6.5s%7D%5C%5C%20%5C%5Ca%20%3D%202.06m%2Fs%5E2)
Therefore, the acceleration of the runner in the given time is 2.06m/s².
Learn more about Equations of Motion: brainly.com/question/18486505