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xeze [42]
3 years ago
9

Which term is defined by the force that moving, charged particles exert on one another?

Physics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

Electromagnetic force

Explanation:

There are four fundamental forces in nature:

- Gravity: it is the force that is exerted between any objects with mass. It is the weakest of all forces, so it is only relevant at planetary scales. It is always attractive, and it has an infinite range.

- Electromagnetic force: it is the force exerted between charged objects and between magnets (it is responsible for electric fields and magnetic fields). It is the 2nd strongest force, and it is the force that holds atoms in a molecule together. It can be attractive or repulsive, and it has an infinite range.

- Strong nuclear force: it is the strongest of all forces. It is responsible for holding the nucleons together inside the nucleus, and it is attractive. It has a very limited range (10^{-15}m), so it is relevant only at very small scales

- Weak nuclear force: it is the force responsible for radioactive decays and neutrino interactions. It also has a very short range (10^{-18} m

Looking at all these definitions, we see that the term that defines the force that acts between charged particles is the electromagnetic force.

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"A short-wave radio antenna is supported by two guy wires, 150 ft and 170 ft long. Each wire is attached to the top of the anten
Nonamiya [84]

Answer:

The anchor points are 78.37 ft and 111.99 ft

Explanation:

If you look at the attached (Fig 1) you will find that the union of antenna and its guy wires forms two right triangles. To solve problems that involve this kind of triangles, you can apply trigonometric functions (sine, cosine, etc) and Pythagoras Theorem. Trigonometric functions states the relation between angles, sides and hypotenuse of a right triangle. If you look Fig2, considering α angle, "b" is the opposite side, "a" the adjacent side and "c" the hypotenuse. Then

a) Sine (α) = b/c it means opposite side/hypotenuse

b) Cosine (α)= a/c, it means adjacent side/hypotenuse

c) Tangent (α) = b/a opposite side/adjacent side.

Pythagoras theorem states that if you called "a" and "b", the sides of the right triangle, and "c" the hypotenuse, then:

                                      a² + b² = c²    

As the problem states the lengths 150 ft and 170 ft represents the value of the hypotenuse of each triangle and 65° is one of the angles of the triangle with 150 ft hypotenuse. So you can solve this using sin (65°) to find the height of the antenna (h) and then the two distances (x and y,).

Sine (65°) = h/ 150 ft ⇒ Sine (65°) x 150ft = h ⇒ h = 127.9 ft.

To find x : Cosine (65°) = x/ 150 ft ⇒ Cosine (65°) x 150 ft = x

⇒ x = 78.37 ft.

And finally, to find y we can apply Pythagoras theorem

(170 ft)² = (127.9 ft)² + y² ⇒ y² = (170 ft)² - (127.9 ft)² ⇒ y = 111.99 ft

Summarizing, the anchor points are 78.37 ft and 111.99 ft

4 0
3 years ago
Which two events are part of the rock cycle?
kozerog [31]

Answer:

B and C

Explanation:

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8 0
2 years ago
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6 0
2 years ago
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If a tennis ball has a density of 0.47 g/cm3, will it float of sink in water?
gogolik [260]

Answer:

it will float because the density of water is 1g/cm³ and is therefore less dense

Explanation:

5 0
2 years ago
A student at the top of a building of height h throws ball A straight upward with speed v0 (3 m/s) and throws ball B straight do
Flauer [41]

Answer:same

Explanation:

Given

ball A initial velocity=3 m/s(upward)

Ball B initial velocity=3 m/s (downward)

Acceleration on both the balls will be acceleration due to gravity which will be downward in direction

Both acceleration is equal

For ball A

maximum height reached is h_1=\frac{3^2}{2g}

After that it starts to move downwards

thus ball have to travel a distance of h_1+h(building height)

so ball A final velocity when it reaches the ground is

v_a^2=2g\left ( h_1+h\right )

v_a^2=2g\left ( 0.458+h\right )

v_a=\sqrt{2g\left ( 0.458+h\right )}

For ball b

v_b^2-\left ( 3\right )^2=2g\left ( h\right )

v_b^2=2g\left ( \frac{3^2}{2g}+h\right )

v_b=\sqrt{2g\left ( 0.458+h\right )}

thus v_a=v_b

5 0
3 years ago
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