The ion in the cathode that gains electrons
Answer:
1) Write the balanced equation:
2C2H6 + 7O2 ---> 4CO2 + 6H2O
2) Determine limiting reagent:
C2H6 ⇒ 13.8 g / 30.0694 g/mol = 0.45894 mol
O2 ⇒ 45.8 g / 31.9988 g/mol = 1.4313 mol
C2H6 ⇒ 0.45894 / 2 = 0.22947
O2 ⇒ 1.4313 / 7 = 0.20447
Oxygen is limiting.
3) Determine theoretical yield of water:
The oxygen : water molar ratio is 7 : 6
7 is to 6 as 1.4313 mol is to x
x = 1.2268286 mol of water
4) Convert moles of water to grams:
1.2268286 mol times 18.015 g/mol = 22.1 g (to three sig figs)
Solution to (b):
14.2 g / 22.1 g = 64.2%
Explanation:
the answer to this question would be true just thought u should know lol xd
Heat of vaporization of water = 540 cal/g
m=1000 g
energy supplied = 5.4 kcal=5400 cal
T1=T2=100 deg. C
so all energy is used to convert to steam
mass of steam produced = 5400 cal /(540 cal/g)
=5400/540 cal *g/cal
=10 g
