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4 years ago

14

According to Newton's first law of motion, which force is expected to cause a body to accelerate? A. unbalanced force B. balance

d force C. weak force D. strong force

2 answers:

Evgen [1.6K]4 years ago

7 0

A. an unbalanced force beacause you can't move a chair for example, without pushing it with more force than the chair.

Irina-Kira [14]4 years ago

5 0

A. an unbalanced force

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vladimir1956 [14]

Newton's first law of motion is often stated as

<span>An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force. Therefore, the answer here is A) Newton's First Law.

Hope this helped ;)
</span>

6 0

3 years ago

Read 2 more answers

A certain comet has a parallax 1/40 as large as the moon. How far away is it (compared to the Moons distance)? Show Work

Ad libitum [116K]

The distance and parallax are inversely related. We can find the distance using the following equation:

$d= \frac{1}{p}$

where d is distance and p is parallax.

We are given the parallax of the comet relative to the moon, and we are looking for the distance to the comet relative to the moon's distance, so wee can plug in the following value:

$d= \frac{1}{ \frac{1}{40} }$

The distance is 40 times as far away as the moon.

3 0

4 years ago

The temperature of a lead fishing weight rises from 26∘c to 38∘c as it absorbs 11.3 j of heat. what is the mass of the fishing w

Nimfa-mama [501]

Given:
ΔT = 38 - 26 = 12°C, temperature change
Q = 11.3 J, heat input
c = 0.128 J/(g-°C), specific heat of lead

Let m = the mass of the lead.
Then
Q = m*c*ΔT
(m g)*(0.128 J/(g-°C))*(12 °C) = 11.3 J
1.536m = 11.3
m = 7.357 g

Answer: 7.36 g (2 sig. figs)

8 0

3 years ago

Four electrons are located at the corners of a square 10.0 nm on a side, with an alpha particle at its midpoint. How much work i

Elis [28]

Four electrons are placed at the corner of a square

So we will first find the electrostatic potential at the center of the square

So here it is given as

$V = 4\frac{kQ}{r}$

here

r = distance of corner of the square from it center

$r = \frac{a}{\sqrt2}$

$r = \frac{10nm}{\sqrt2} = 7.07 nm$

$Q = e = -1.6 * 10^{-19} C$

now the net potential is given as

$V = \frac{4 * 9*10^9 * (-1.6 * 10^{-19})}{7.07 * 10^{-9}}$

$V = 0.815 V$

now potential energy of alpha particle at this position

$U_i = qV = 2*1.6 * 10^{-19} * (-0.815) = -2.6 * 10^{-19} J$

Now at the mid point of one of the side

Electrostatic potential is given as

$V = 2\frac{kQ}{r_1} + 2\frac{kQ}{r_2}$

here we know that

$r_1 = \frac{a}{2} = 5 nm$

$r_2 = \sqrt{(a/2)^2 + a^2} = \frac{\sqrt5 a}{2}$

$r_2 = 11.2 nm$

now potential is given as

$V = 2\frac{9 * 10^9 * (-1.6 * 10^{-19})}{5 * 10^{-9}} + 2\frac{9*10^9 * (-1.6 * 10^{-19})}{11.2 * 10^{-9}}$

$V = -0.576 - 0.257 = -0.833 V$

now final potential energy is given as

$U_f = q*V = 2*1.6 * 10^{-19}* (-0.833) = -2.67 * 10^{-19} J$

Now work done in this process is given as

$W = U_f - U_i$

$W = (-0.267 * 10^{-19}) - (-0.26 * 10^{-19}}$

$W = -7 * 10^{-22} J$

8 0

3 years ago

Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

vichka [17]

Answer:

Option 2 - Standard deviation

Explanation:

To find : Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

Solution :

Standard deviation is defined as,

It is a mathematical measure that is used to evaluate the difference between the mean value of a set of number and each value in the group.

It is calculated as the square root of variance by determining the variation between each data point relative to the mean.

The measure of dispersion that indicates how much scores in a sample vary around the mean of the sample is the standard deviation.

Therefore, option 2 is correct.

3 0

3 years ago