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alukav5142 [94]
3 years ago
14

Will Mark Brainliest!

Chemistry
2 answers:
BigorU [14]3 years ago
7 0

Answer:

when water changes from a liquid on earths surface to a gas in the atmosphere,this is known as evaporation

Sergeu [11.5K]3 years ago
5 0

Answer: Evaporation!

Explanation:

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Una pieza de silicio tiene un volumen de 8 cm3. ¿Cuál es su masa? *
Maurinko [17]

Answer:

el volumen es igual a masa decidida por densidad

8 0
2 years ago
A student mixes 33.0 mL of 2.70 M Pb ( NO 3 ) 2 ( aq ) with 20.0 mL of 0.00157 M NaI ( aq ) . How many moles of PbI 2 ( s ) prec
GalinKa [24]

<u>Answer:</u> The moles of precipitate (lead (II) iodide) produced is 1.57\times 10^{-5} moles

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For lead (II) nitrate:</u>

Molarity of lead (II) nitrate solution = 2.70 M

Volume of solution = 33.0 mL = 0.033 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

2.70M=\frac{\text{Moles of lead (II) nitrate}}{0.033L}\\\\\text{Moles of lead (II) nitrate}=(2.70mol/L\times 0.0330L)=0.0891mol

  • <u>For NaI:</u>

Molarity of NaI solution = 0.00157 M

Volume of solution = 20.0 mL = 0.020 L

Putting values in equation 1, we get:

0.00157M=\frac{\text{Moles of NaI}}{0.020L}\\\\\text{Moles of NaI}=(0.00157mol/L\times 0.0200L)=3.14\times 10^{-5}mol

For the given chemical reaction:

Pb(NO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaNO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts with 1 mole of lead (II) nitrate

So, 3.14\times 10^{-5} moles of NaI will react with = \frac{1}{2}\times 3.14\times 10^{-5}=1.57\times 10^{-5}mol of lead (II) nitrate

As, given amount of lead (II) nitrate is more than the required amount. So, it is considered as an excess reagent.

Thus, NaI is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 3.14\times 10^{-5} moles of NaI will produce = \frac{1}{2}\times 3.14\times 10^{-5}=1.57\times 10^{-5}moles of lead (II) iodide

Hence, the moles of precipitate (lead (II) iodide) produced is 1.57\times 10^{-5} moles

4 0
3 years ago
What molecules can be made using hydrogen, carbon, and nitrogen?​
Yuki888 [10]

Answer:

Ammonia

Explanation:

Ammonia is the simplest possible molecule made with nitrogen and hydrogen. Methane is the simplest possible molecule made of carbon and hydrogen. Methanol is like methane, but it also has one oxygen atom as well.

8 0
3 years ago
Lily took 57 seconds to walk from classroom to library. If the distance between the classroom and library was 38 m, at what aver
slamgirl [31]
1.5 sorry if I’m wrong!
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3 years ago
What best describes the goals of scientific investigation and technological development?
torisob [31]

Answer:

Scientific investigation aims to design and implement an experiment to learn new information, where

development aims to design a product to solve a problem.

Explanation:

8 0
3 years ago
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