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3 years ago

Which is greater - the average depth of the ocean, or the average elevation of the continents?

Physics

2 answers:

Elza [17]3 years ago

8 0

The average depth of the ocean

s344n2d4d5 [400]3 years ago

5 0

<em>The average width of a continental shelf is 65 kilometers (40 miles). Most continental shelves are broad, gently sloping plains covered by relatively shallow water. Water depth over the continental shelves averages about 60 meters (200 feet) :) Have a good day!!!</em>

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Students have 4 different pairs of sunglasses, each with lenses where the polarization filter is oriented in different direction

AysviL [449]

Answer:

the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.

Explanation:

The glare is caused by the reflection of light in the water, the polarization of the reflected light is polarized in a direction parallel to the surface of the water, the polarization is total for the angles

n = tan $\theta_{p}$

\theta_{p} = tan⁻¹ n

the refractive index for seawater is 1.33

\theta_{p}= tan⁻¹ 1.33

\theta_{p} = 53º

for this angle the light is totally polarized, for the other angles the polarization is partial.

Based on this, the lenses must eliminate this polarization, so its polarization direction must have 90º with respect to this polarization,

\theta_{lens} = 53 +90

\theta_{lens}= 143º

Therefore, the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.

A lens that could work is one that is polarized 45º with respect to the vertical.

6 0

3 years ago

A laser beam of wavelength 439.4 nm is inci- dent on two slits 0.306 mm apart.

Ivahew [28]

Constructive interference happens when this condition is satisfied:
$dsin(\theta)=m\lambda; m=1,2,3,4,5,...$
This means that the difference in the distance traveled by the waves, from the slit to the screen, is equal to the whole multiple of the wavelength.
If we say that the distance between two interference fringes is much smaller than the distance from the slit to the screen, we can use the following approximation:
$sin(\theta)=\frac{y}{L}$
Finally for the bright spots we have:
$y=\frac{m\lambda L}{d}$
The spacing between bright spots is:
$y=\frac{\lambda L}{d}=\frac{6.08\cdot 439.4\cdot 10^{-9}}{0.306 \cdot 10^{-3}}=8.73mm$

8 0

3 years ago

Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write

Eva8 [605]

Answer:

R = ( 4.831 m , 1.469 m )

Magnitude of R = 5.049 m

Direction of R relative to the x axis= 16°54'33'

Explanation:

Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

$\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )$

where $| \vec{A} |$ its the magnitude and θ.

So, for our vectors, we will have:

$\vec{D}= 3.00 m \ ( \ cos(315) \ , \ sin (315) \ )$

$\vec{D}= ( 2.121 m , -2.121 m )$

and

$\vec{E}= 4.50 m \ ( \ cos(53.0) \ , \ sin (53.0) \ )$

$\vec{E}= ( 2.71 m , 3.59 m )$

Now, we can take the sum of the vectors

$\vec{R} = \vec{D} + \vec{E}$

$\vec{R} = ( 2.121 \ m , -2.121 \ m ) + ( 2.71 \ m , 3.59 \ m )$

$\vec{R} = ( 2.121 \ m + 2.71 \ m , -2.121 \ m + 3.59 \ m )$

$\vec{R} = ( 4.831 \ m , 1.469 \ m )$

This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem

$|\vec{R}| = \sqrt{R_x^2 + R_y^2}$

$|\vec{R}| = \sqrt{(4.831 m)^2 + (1.469 m)^2}$

$|\vec{R}| = \sqrt{23.338 m^2 + 2.158 m^2}$

$|\vec{R}| = \sqrt{25.496 m^2}$

$|\vec{R}| = 5.049 m$

To find the direction, we can use

$\theta = arctan(\frac{R_y}{R_x})$

$\theta = arctan(\frac{1.469 \ m}{4.831 \ m})$

$\theta = arctan(0.304)$

$\theta = 16\°54'33''$

As we are in the first quadrant, this is relative to the x axis.

3 0

3 years ago

Which of the following best defines speed? (3 points) a It is an object's speed at a specific point in time. b It is the distanc

djverab [1.8K]

Answer:

Explanation:

they are all almost correct.

c is the only fully correct option

6 0

2 years ago

Which BMI standard for teens is considered under weight?

Lena [83]

First let’s pick one at random

Less than 5 percentile

That means they lined 100 kids up and less than 5% of them are that certain weight.

So if you apply this to every option you will see the answer is
A). Less than 5 percentile

3 0

3 years ago

Read 2 more answers