Answer:
-1.65
Explanation:
First of all, we find the position of the image by using the lens equation:
where:
f is the focal length of the lens
p is the distance of the object from the lens
q is the distance of the image from the lens
For the lens in this problem:
f = 21.0 cm (the focal length of a convex lens is positive)
p = 33.7 cm
Solving for q, we find the position of the image:
Then, the magnification of the image is given by:
And substituting,
Which means that the image is inverted (negative sign) and enlarged (because M is larger than 1).
That all depends on the angle between the two forces.
It could be anything between 1.3 m/s² in the direction of the larger force, if
they're in opposite directions, all the way around to 6.04 m/s² in the direction
of both of them if they're both in the same direction.
That includes magnitudes between 1.3n and 6.04n directed somewhere between
the two forces if they're in different, unrelated directions.
Answer : The correct option is, (A) 
Explanation :
The formula used for speed of sound wave is:
where,
v = speed of sound wave = 
= density of medium = 
B = bulk modulus = ?
As the formula is,
Squaring on both the sides, we get:
Now put all the given values in the above formula, we get:
Therefore, the bulk modulus of the medium is
B is the answer!!!!!!!!!!!!!
Answer:
there are 3.018 kcal= 3018 cal per gram of candy
Explanation:
If the assume that the calorimeter is perfectly insulated, then all the heat released by the combustion is absorbed by the calorimeter.
Also knowing that Q= C * ΔT , where C= heat capacity of the calorimeter , ΔT= temperature change , Q = heat released by the combustion of the candy
replacing values
Q = C * ΔT = 33.90 kJ/°C * 2.46°C = 83.394 kJ
since Q is the heat released when burned all the mass m of the candy, the number of calories per gram of candy will be
q = Q/m =83.394 kJ / 6.60 g = 12.635 kJ/g
q = 12.635 kJ/g * 1 kcal / 4.186 kJ = 3.018 kcal per gram of candy
