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mel-nik [20]
3 years ago
15

What two things do all matter have in common?

Chemistry
2 answers:
lord [1]3 years ago
7 0

Answer:

I believe that is inertia and mass.

Explanation:

ELEN [110]3 years ago
3 0

Answer:

mass and occupies space

Explanation:

matter is made up of mass and mass takes up space

You might be interested in
Convert 2.55 moles of water to grams.
Vlada [557]

Explanation:

No of mass = no of moles × molar mass

=2.55 × 18 g

= 45.9 g

6 0
3 years ago
4) What is one advantage of using non-renewable resources?
vlabodo [156]

Answer:

The main advantages of non-renewable energies is that they are abundant and affordable. For example, oil and diesel are still good choices for powering vehicles. Non-renewable energy is cost effective and easier to product and use.

Explanation:

there yah go

5 0
3 years ago
What is the molar concentration of chloride ions in a
Yanka [14]

Answer:

The concentration of chloride ions in the final solution is 3 M.

Explanation:

The number of moles present in a solution can be calculated as follows:

number of moles = concentration in molarity * volume

In 100 ml of a 2 M KCl solution, there will be (0.1 l * 2mol/l) 0.2 mol Cl⁻

For every mol of CaCl₂, there are 2 moles of Cl⁻, then, the number of moles of Cl⁻ in 50 l of a 1.5 M solution will be:

number of moles of Cl⁻ = 2 * number of moles of  CaCl₂

number of moles of Cl⁻ = 2 ( 50 l * 1.5 mol / l ) = 150 mol Cl⁻

The total number of moles of Cl⁻ present in the solution will be (150 mol + 0.2 mol ) 150.2 mol.

Assuming ideal behavior, the volume of the final solution will be ( 50 l + 0.1 l) 50.1 l. The molar concentration of chloride ions will be:

Concentration = number of moles of Cl⁻ / volume

Concentration = 150.2 mol / 50.1 l = 3.0 M

8 0
3 years ago
Which is the correct set of products for the acid-base neutralization reaction between sulfuric acid (H2SO4) and potassium hydro
Elis [28]

Answer:

H2O and K2SO4

Explanation:

3 0
3 years ago
I need this answer quick please show work
Ainat [17]

Answer:

The answer to your question is 25.2 g of acetic acid.

Explanation:

Data

[Acetic acid] = 0.839 M

Volume = 0.5 L

Molecular weight = 60.05 g/mol

Process

1.- Calculate the number of moles of acetic acid

    Molarity = moles / volume

-Solve for moles

    moles = Molarity x volume

-Substitution

    moles = (0.839)(0.5)

-Result

    moles = 0.4195

2.- Calculate the mass of acetic acid using proportions and cross multiplications

                   60.05 g ----------------------- 1 mol

                        x        ----------------------- 0.4195 moles

                        x = (0.4195 x 60.05) / 1

                        x = 25.19 g

3.- Conclusion

25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M

               

4 0
3 years ago
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