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Marizza181 [45]
3 years ago
10

How many molecules of molecular oxygen react with four molecules of NH3 to form four molecules of nitrogen monoxide and six mole

cules of water?
Chemistry
2 answers:
Lerok [7]3 years ago
6 0

Answer:

5 molecules of O2 reacted.

Explanation:

From the question, were told that 4 molecules of NH3 reacted with O2 to form 4 molecules of NO and 6 molecules of water. To know the molecules of O2 that reacted, we must generate a balanced equation. This is illustrated below:

4NH3 + O2 —> 4NO + 6H2O

From the above equation, we have a total of 10 atoms of O2 on the right side of the equation and a total of 2 atoms of O2 on the left side. To balance the equation, put 5 in front of O2 as shown below:

4NH3 + 5O2 —> 4NO + 6H2O

Now, the equation is balanced.

From the balanced equation, 5 molecules of O2 reacted.

Ymorist [56]3 years ago
5 0

Answer:

We need 5 molecules of molecular oxygen

Explanation:

Step 1: Data given

molecular oxygen = O2

nitrogen monoxide = NO

water = H2O

Step 2: The balanced equation

4NH3 + O2 → 4NO + 6H2O

Step 3:

On the left side we hace 2x O (in O2), on the right side we have 10x O ( 4x in NO and 6x in 6H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side) by 5.

4NH3 + 5O2 → 4NO + 6H2O

We need 5 molecules of molecular oxygen

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A 2.0 molal sugar solution has approximately the same freezing point as 1.0 molal solution of 1) CaCl2 2) CH3COOH 3) NaCl 4) C2H
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3) NaCl.

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<em>∵ ΔTf = iKf.m</em>

where, <em>i</em> is the van 't Hoff factor.

<em>Kf </em>is the molal depression freezing constant.

<em>m</em> is the molality of the solute.

<em>The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. </em>

<em></em>

  • For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<em>So, for sugar: i = 1.</em>

<em>∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.</em>

<em></em>

  • For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

<em>So, i for NaCl = 2.</em>

<em>∴ ΔTf for NaCl = iKf.m = (2)(Kf)(1.0 m) = 2 Kf.</em>

<em></em>

<em>So, the right choice is: 3) NaCl.</em>

<em></em>

8 0
3 years ago
30 its ASAP!!!! What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?
USPshnik [31]
Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 &deg; C = 23+273.15 = 296.15 &deg; K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = <span>0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)

</span>
5 0
4 years ago
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