Answer:The Urban heat island temperature will be REDUCED.
Two Impacts of Rooftop gardens
1) provision of shade against Sunlight.
2) It helps to purify the air around the building.
Explanation: Rooftop gardens are gardens made on top of the roofs of buildings, it is a Green initiative aimed at helping to improve the overall Environment.
Rooftop gardens have several significant benefits which includes
Reduction of the surrounding temperatures and the Urban heat Island temperatures.
Rooftop gardens helps to shade the roof from the direct impacts of harsh weather conditions.
Generally, plants are known as air purifiers as they remove the excess Carbondioxide around the environment through photosynthesis, and they also help to release water vapor which will help to improve the humidity of the environment.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a) 
b) 
Explanation:
The explanation is shown on the second and third uploaded image
The project or the site manager is responsible for monitoring or verifying the aspects of the construction process.
The site or the project manager is the individual that is responsible for the adherence to quality and guidance on the construction site.
The site or project manager has the following tasks
- ensuring safety on the site
- Monitoring the progress or the work that is being done
- Sourcing materials
- Solving problems
In conclusion, the project manager monitors and verifies aspects of the construction process.
Read more on brainly.com/question/24887827?referrer=searchResults
Answer:
The average thickness of the blubber is<u> 0.077 m</u>
Explanation:
Here, we want to calculate the average thickness of the Walrus blubber.
We employ a mathematical formula to calculate this;
The rate of heat transfer(H) through the Walrus blubber = dQ/dT = KA(T2-T1)/L
Where dQ is the change in amount of heat transferred
dT is the temperature gradient(change in temperature) i.e T2-T1
dQ/dT = 220 W
K is the conductivity of fatty tissue without blood = 0.20 (J/s · m · °C)
A is the surface area which is 2.23 m^2
T2 = 37.0 °C
T1 = -1.0 °C
L is ?
We can rewrite the equation in terms of L as follows;
L × dQ/dT = KA(T2-T1)
L = KA(T2-T1) ÷ dQ/dT
Imputing the values listed above;
L = (0.2 * 2.23)(37-(-1))/220
L = (0.2 * 2.23 * 38)/220 = 16.948/220 = 0.077 m
