Answer:
0.019 g.
Explanation:
- Firstly, we need to find the no. of moles of oxygen gas:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 1.02 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).
∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.
- To find the mass of oxygen gas, we have:
<em>no. of moles = mass/molar mass.</em>
<em></em>
∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.
Answer:
the correct answer is $2.06
Explanation:
<em>hope</em><em> </em><em>it'll</em><em> </em><em>help you</em><em>.</em><em>.</em><em>.</em>
Answer:
Are u a boy or a girl so we can form a study group and the answer is C
Thermal energy is added to the water
Answer:
8.3lb of fat were removed
Explanation:
To solve this problem we need to convert the liters of fat removed to mL. Using the mL and density we can find the grams. To convert grams to pounds we must use (1lb = 453.592g):
<em>mL fat:</em>
4.0L * (1000mL / 1L) = 4000mL
<em>g fat:</em>
4000mL * (0.94g / mL) = 3760g of fat
<em>lb fat:</em>
3760g of fat * (1lb / 453.592g) =
<h3>8.3lb of fat were removed</h3>