1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gennadij [26K]
3 years ago
12

Is the sun a transparent object

Physics
1 answer:
son4ous [18]3 years ago
7 0
No because it is dense and opaque
You might be interested in
A bullet starting from rest accelerates uniformly at a rate of 1,250 meters per square second. What is the bullet's speed after
Tatiana [17]

Answer:

125,000

Explanation:

8 0
3 years ago
I don’t know how to answer this question? Can anyone help?
VMariaS [17]

Answer:

F=ma

here F is force, m is mass and a is accelaration,

According to the question,

F=3*F= 3F

m= 1/3 of m= m/3

a= ?

so the equation becomes,

3F= m/3*a

3F*3= ma

9F=ma

F= ma/9

Therefore accelaration reduces by 1/9.

I am not very sure.

7 0
3 years ago
Help
photoshop1234 [79]

Answer:

It conserves both energy and momentum in the collision at the same time. By design, when the balls collide the strings that hold them up are vertical (assuming balls are only swung from one side).

Explanation:

Hope This Helps!!

7 0
2 years ago
A(n) 82.7 kg boxer has his first match in the Canal Zone with gravitational acceleration 9.782 m/s 2 and his second match at the
Annette [7]

Answer:

82.7 kg

Explanation:

the mass of the boxer remains unchanged, this is because mass is a measure of the quantity of matter in an object irrespective of its location and the gravitational force acting at its location. this means mass is independent of the gravitational acceleration hence it remains the same 82.7 kg. its unit is in kilograms (Kg).

6 0
2 years ago
Janessa got through high school easily because she could remember what her teachers said in class and their tests never covered
VMariaS [17]
<span>CorrectThe direction of the electric field stays the same regardless of the sign of the charges that are free to move in theconductor.Mathematically, you can see that this must be true since the expression you derived for the electric field isindependent of .Physically, this is because the force due to the magnetic field changes sign as well and causes positive charges tomove in the direction (as opposed to pushing negative charges in the direction). Therefore the result isalways the same: positive charges on the side and negative charges on the side. Because the electric fieldgoes from positive to negative charges will always point in the direction (given the original directions of</span>
8 0
3 years ago
Other questions:
  • You and your surfing buddy are waiting to catch a wave a few hundred meters off the beach. The waves are conveniently sinusoidal
    10·2 answers
  • List one way to take advantage of creating even more kinetic energy on this particular technologically advanced field
    14·1 answer
  • How do you calculate the electric force by object a exerted on object a (itself)?
    6·1 answer
  • The total electric field consists of the vector sum of two parts. One part has a magnitude of E1 = 1300 N/C and points at an ang
    10·1 answer
  • Which of the following oceans lies between North America, South America, Europe and Africa?
    5·2 answers
  • Which of the following is a primary source?
    13·1 answer
  • The law of conservation of momentum states that, if left alone, what happens to the total momentum of two interacting objects th
    8·2 answers
  • The space shuttle slows down from 1200 km/hr to 400 km/hr over 10 seconds. What is the space shuttles deceleration?
    11·1 answer
  • Deonte’s family sees a solar panel display and considers using solar power for their home. Deonte knows that solar energy is a n
    5·1 answer
  • The heaviest invertebrate is the giant squid, which is estimated to have a weight of about 0.37 tons spread out over its length
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!