Question

How much force would cause a 120 kg object to decelerate from a rate of 16m/s to 13 m/s in 5 seconds

Answer 1

$a=\frac{13m/s-16m/s}{5s} \\a=-0.6 m/s^2\\then\\F=m.a\\F=(120kg)(-0.6 m/s^2)\\F=72 N$