Answer:
= -457.9 kJ and reaction is product favored.
Explanation:
The given reaction is associated with 2 moles of ![NH_{3}](https://tex.z-dn.net/?f=NH_%7B3%7D)
Standard free energy change of the reaction (
) is given as:
, where T represents temperature in kelvin scale
So, ![\Delta G^{0}=(-683.1\times 10^{3})J-(273K\times -365.6J/K)=-583291.2J](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28-683.1%5Ctimes%2010%5E%7B3%7D%29J-%28273K%5Ctimes%20-365.6J%2FK%29%3D-583291.2J)
So, for the reaction of 1.57 moles of
, ![\Delta G^{0}=(\frac{1.57}{2})\times -583291.2J=-457883.592J=-457.9kJ](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28%5Cfrac%7B1.57%7D%7B2%7D%29%5Ctimes%20-583291.2J%3D-457883.592J%3D-457.9kJ)
As,
is negative therefore reaction is product favored under standard condition.
I don't know how to draw it but I can solve it
Sodium. It reacts with most of every other element.
The average mass of an atom is calculated with the formula:
average mass = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2) + ... an so on
For the boron we have two isotopes, so the formula will become:
average mass of boron = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2)
We plug in the values:
10.81 = 0.1980 × 10.012938 + 0.8020 × mass of isotope (2)
10.81 = 1.98 + 0.8020 × mass of isotope (2)
10.81 - 1.98 = 0.8020 × mass of isotope (2)
8.83 = 0.8020 × mass of isotope (2)
mass of isotope (2) = 8.83 / 0.8020
mass of isotope (2) = 11.009975
mass of isotope (1) = 10.012938 (given by the question)
Answer:
Propyne can be converted to the acetone when it is made to undergo the reaction with mercuric sulphate followed by hydrolysis and thus, resultant product, thus formed is acetone.
Explanation: