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inna [77]
3 years ago
9

You are attempting to row across a stream in your rowboat. Your paddling speed relative to still water is 3.0 m/s (i.e., if you

were to paddle in water without a current, you would move with a speed of 3.0 m/s). You head off by rowing directly north, across the stream.
Now assume that the stream flows east at 4.0 m/s. Draw the vectors \vec{v}_w, representing the velocity of the stream, and \vec{v}_{tot}, representing the velocity of your rowboat relative to the stream bank. Be sure to draw both vectors.
Draw \vec{v}_{tot} and \vec{v}_w starting at the tail and tip of \vec{v}_{still} respectively. The location, orientation and length of the vectors should be appropriate. Each vector's length is displayed in meters per second.

Physics
1 answer:
Nataliya [291]3 years ago
6 0

Answer:

Please check the attached file for the diagram

Explanation:

The velocity of the of the rowboat V_{tot}  through the river is the resultant velocity. It is obtained taking a vector sum of the velocity in still water and the velocity of the river.

There are several ways to take this vector sum, but the question makes it simple for us to use Pythagoras's theorem because the East and North directions are perpendicular to each other.

Hence;

V_{tot}^2=V_{still}^2+V_{w}^2\\V_{tot}^2=3^2+4^2

V_{tot}=\sqrt{3^2+4^2}\\ V_{tot}=\sqrt{25}=5m/s

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Explanation:

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3 years ago
Un paracaidista desciende desde 6 000 m de altura. Si la masa, con su equipo, es de 65 kg, ¿cuánto valdrá su energía potencial e
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Explanation:

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3 0
3 years ago
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
expeople1 [14]

Answer:

3.735×10⁻⁶ N

Explanation:

From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

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Answer:

A

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