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Anuta_ua [19.1K]
3 years ago
10

This formula equation is unbalanced

Chemistry
1 answer:
alexandr402 [8]3 years ago
3 0

Answer:

coefficient is 2

Explanation:

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An neutral atom has 40 protons and 10 neutrons what is the mass number
olya-2409 [2.1K]

Answer:

50

Explanation:

40-10 = 30…...…............

5 0
3 years ago
Read 2 more answers
Eli states that sodium phosphate is a mixture because it is composed of both sodium ions and phosphate ions.
KonstantinChe [14]

Answer is: c. It is incorrect because sodium phosphate is a compound that has a single composition.

Sodium phosphate is chemical compound composed of atoms connected with chemical bonds.

Pure substance is made of only one type of atom (element) or only one type of molecule (compound), it has definite and constant composition with distinct chemical properties.

Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

7 0
3 years ago
Read 2 more answers
A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg
Furkat [3]

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a\sqrt{3}/4

Given

a = 360 pm

Therefore

r = r = radius = 360\sqrt{3}/4= 155.88 pm

Or

156 pm

3 0
3 years ago
What is the wavelength of radiation emitted when an electron goes from the n = 7 to the n = 4 level of the Bohr hydrogen atom? G
Phantasy [73]

Answer:

the wavelength of radiation emitted  is \mathbf{\lambda= 2169.62 \ nm}

Explanation:

The energy of the Bohr's hydrogen atom can be expressed with the formula:

\mathtt{E_n =- \dfrac{13.6\ ev}{n^2}}

For n = 7:

\mathtt{E_7 =- \dfrac{13.6\ ev}{7^2}}

\mathtt{E_7 =-0.27755 \ eV}

For n = 4

\mathtt{E_4=- \dfrac{13.6\ ev}{4^2}}

\mathtt{E_4 =- 0.85\ eV}

The  electron goes from the n = 7 to the n = 4, then :

\mathtt{E_7-E_4 = (-0.27755 - (-0.85) ) \ eV}

\mathtt{= 0.57245\ eV}

Wavelength of the radiation emitted:

\mathtt{\lambda= \dfrac{hc}{0.57245 \ eV}}

where;

hc  = 1242 eV.nm

\mathtt{\lambda= \dfrac{1242 \ eV.nm }{0.57245 \ eV}}

\mathbf{\lambda= 2169.62 \ nm}

4 0
3 years ago
Catalina received her bank statement showing a savings account balance of $1,056.33. Not shown on the statement were a deposit o
Dafna1 [17]
$724.73 this would be the answer because if you subtract 320.50 and 86.10 from the 1056.33 then add 75 you get 724.73
6 0
3 years ago
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