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3 years ago

7

Ignoring air resistance, if you throw a baseball from first base upwards toward a friend in left field, and the baseball leaves

your hand at a speed of 15 meters per second, how fast will the ball be going when your friend catches it? A. 15 m/s B. less than 15 m/s C. more than 15 m/s D. It would depend on the distance the friend is from you.

2 answers:

larisa86 [58]3 years ago

4 0

Answer:

A: 15 m/s

Explanation:

If air resistance was not there, then the ball would not stop moving unless your friend, gravity, and the ground catches it.

Trava [24]3 years ago

4 0

A) 15 m/s HOPE THAT HELPS!

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. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mas

loris [4]

The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg

Aspartame has the chemical formula C14H18N2O5

C = 12, H = 1, N = 14, O = 16

(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)

= 168 + 18 + 28 + 80

= 294 amu

(b) Mass of 1 molecule of aspartame = mole x molar mass

= 1 x 294

= 294 g

Converting 294 g to kg = 294/1000

= 0.294 kg

More on mole and molar mass can be found here: brainly.com/question/6613610

7 0

3 years ago

A cubic box of volume 5.1 x 10 -2m3 is

I am Lyosha [343]

Answer:

21544 N

Explanation:

Let the atmospheric pressure be 101325 Pa

The side length of the cubic box:

$V = d^3 = 0.051m^3$

$d = \sqrt[3]{V} = \sqrt[3]{0.051} = 0.371 m$

The area of the cubic box:

$A = d^2 = 0.371^2 = 0.1375 m^2$

20 C = 20 + 273 = 293 K

180 C = 180 + 273 = 453 K

As the volume of the air inside the closed cube is not changed, assume the ideal gas law we have

$\frac{P_1}{T_1} = \frac{P_2}{T_2}$

Where P1 = 101325 Pa and T1 = 293K are the original atmospheric pressure and temperature. P2 and T2 = 453 are the new pressure and temperature after the cube gets heat up

$P_2 = P_1\frac{T_2}{T_1} = 101325\frac{453}{293} = 156656 Pa$

The net force on each side of the box it its pressure times side area

$F = P_2A = 156656 * 0.1375 = 21544 N$

8 0

3 years ago

Alice and Bob sit on a see saw, that consists of a uniform beam of mass 20kg and a fulcrum rock, that acts as a pivot point. The

tankabanditka [31]

Answer:

Explanation:

Given

Mass of alice $M_a=50 kg$

Mass of bob $M_b=70 kg$

Mass of beam $M=20 kg$

Suppose fulcrum is at distance of d from bob thus From diagram

Equating torque i.e. torque of Bob,Alice and beam must cancel out each other to be balanced

$500\times (8-d)+20\times (4-d)=70\times d$

$400-50d+80-2d=70d$

$480=140d$

$d=\frac{480}{140}$

$d=3.43 m$

5 0

4 years ago

A force of 70 N is inclined at an angle

Bad White [126]

Answer:

The horizontal component of the 70 N force = 35·√3 N

The vertical component of the 70 N force = 35 N

Explanation:

The magnitude of the given force, F = 70 N

The angle of inclination of the given force to the horizontal, θ = 30°

By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, $F_y$ , as follows;

The horizontal component of the given force = Fₓ = F × cos(θ)

Substituting the values, we have;

The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N

The vertical component of the given force = $F_y$ = F × sin(θ)

Substituting the values, we have;

The vertical component of the 70 N force, $F_y$ = 70 × sin(30°) = 35 N.

5 0

3 years ago

A motorcycle traveling at 36 m/s slams on the brakes to avoid an accident. The motorcycle skids 23m before stoping. What is the

Svetach [21]

Since the motor cycle was moving at 36 m/s before the brakes were applied, the initial velocity
$u = 36 {ms}^{ - 1}$
The motorcycle traveled 23m before stopping, that means
$s = 23m$
Since the motorcycle stopped moving the final velocity is zero.

$v = 0{ms}^{ - 1}$
We can use this 'suvat' equation of linear motion.

${v}^{2} = {u}^{2} + 2as$
Plugging in the above values gives,

${0}^{2} = {36}^{2} + 2a(23)$

$0 = 1296+ 46a$
$46a = - 1296$
$a = - 28.2 {ms}^{ - 2}$

We can use the equation
$v = u + at$
to find the time the motorcycle took to stop.

$0 = 36 + - 28.2t$
$- 36 = - 28.2t$
$t = 1.3s$

8 0

3 years ago