1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goblinko [34]
2 years ago
7

Ignoring air resistance, if you throw a baseball from first base upwards toward a friend in left field, and the baseball leaves

your hand at a speed of 15 meters per second, how fast will the ball be going when your friend catches it? A. 15 m/s B. less than 15 m/s C. more than 15 m/s D. It would depend on the distance the friend is from you.
Physics
2 answers:
larisa86 [58]2 years ago
4 0

Answer:

A: 15 m/s

Explanation:

If air resistance was not there, then the ball would not stop moving unless your friend, gravity, and the ground catches it.

Trava [24]2 years ago
4 0
A) 15 m/s HOPE THAT HELPS!
You might be interested in
Garrett Hardin's "Tragedy of the Commons" describes the tendency of people to overuse publicly-owned natural resources until the
Aliun [14]

Answer:

is it bad if i keep thinking about p ussy

Explanation:

8 0
3 years ago
What type of appeal does Gore mostly use to persuade the audience?
Mazyrski [523]
I thinks its He uses proof to show the evidence is relevant. But im not totally positive on it hope this helps
8 0
3 years ago
Read 2 more answers
What change in entropy occurs when a 0.15 kg ice cube at -18 °C is transformed into steam at 120 °c 4.
Studentka2010 [4]

<u>Answer:</u> The change in entropy of the given process is 1324.8 J/K

<u>Explanation:</u>

The processes involved in the given problem are:

1.)H_2O(s)(-18^oC,255K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\3.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(100^oC,373K)\\4.)H_2O(l)(100^oC,373K)\rightarrow H_2O(g)(100^oC,373K)\\5.)H_2O(g)(100^oC,373K)\rightarrow H_2O(g)(120^oC,393K)

Pressure is taken as constant.

To calculate the entropy change for same phase at different temperature, we use the equation:

\Delta S=m\times C_{p,m}\times \ln (\frac{T_2}{T_1})      .......(1)

where,

\Delta S = Entropy change

C_{p,m} = specific heat capacity of medium

m = mass of ice = 0.15 kg = 150 g    (Conversion factor: 1 kg = 1000 g)

T_2 = final temperature

T_1 = initial temperature

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=m\times \frac{\Delta H_{f,v}}{T}      .......(2)

where,

\Delta S = Entropy change

m = mass of ice

\Delta H_{f,v} = enthalpy of fusion of vaporization

T = temperature of the system

Calculating the entropy change for each process:

  • <u>For process 1:</u>

We are given:

m=150g\\C_{p,s}=2.06J/gK\\T_1=255K\\T_2=273K

Putting values in equation 1, we get:

\Delta S_1=150g\times 2.06J/g.K\times \ln(\frac{273K}{255K})\\\\\Delta S_1=21.1J/K

  • <u>For process 2:</u>

We are given:

m=150g\\\Delta H_{fusion}=334.16J/g\\T=273K

Putting values in equation 2, we get:

\Delta S_2=\frac{150g\times 334.16J/g}{273K}\\\\\Delta S_2=183.6J/K

  • <u>For process 3:</u>

We are given:

m=150g\\C_{p,l}=4.184J/gK\\T_1=273K\\T_2=373K

Putting values in equation 1, we get:

\Delta S_3=150g\times 4.184J/g.K\times \ln(\frac{373K}{273K})\\\\\Delta S_3=195.9J/K

  • <u>For process 4:</u>

We are given:

m=150g\\\Delta H_{vaporization}=2259J/g\\T=373K

Putting values in equation 2, we get:

\Delta S_2=\frac{150g\times 2259J/g}{373K}\\\\\Delta S_2=908.4J/K

  • <u>For process 5:</u>

We are given:

m=150g\\C_{p,g}=2.02J/gK\\T_1=373K\\T_2=393K

Putting values in equation 1, we get:

\Delta S_5=150g\times 2.02J/g.K\times \ln(\frac{393K}{373K})\\\\\Delta S_5=15.8J/K

Total entropy change for the process = \Delta S_1+\Delta S_2+\Delta S_3+\Delta S_4+\Delta S_5

Total entropy change for the process = [21.1+183.6+195.9+908.4+15.8]J/K=1324.8J/K

Hence, the change in entropy of the given process is 1324.8 J/K

4 0
3 years ago
How much force was applied to an object if was moved 2 meters and the work done on the object was 8 joules?
serious [3.7K]

Answer:

The answer is 4N or B

Explanation:

Just the equation W = F x D.

We have W = 8 J and D = 2 m using algebra ....

8J/2m = F ... F = 4.

6 0
3 years ago
Read 2 more answers
How does vegetation in the soil affect the rate of erosion
avanturin [10]

Answer:

Plants slow down water as it flows over the land and this allows much of the rain to soak into the ground. Plant roots hold the soil in position and prevent it from being blown or washed away. Plants break the impact of a raindrop before it hits the soil, reducing the soil's ability to erode.

Explanation:

4 0
3 years ago
Other questions:
  • Now assume that the water is contained in a 0.1-kg aluminum pot (cAl = 900 J/kg-K) that is initially at 293 K just like the wate
    11·1 answer
  • The weightlifter's internal store of energy decreased when he lifted the bar.
    10·1 answer
  • Define work done against friction<br>(helpp)​
    15·1 answer
  • I need help in my physics class and show me how it’s done
    15·1 answer
  • Clear cutting has a similar effect as controlled burning of a forest. <br><br> True<br><br> False
    6·2 answers
  • A 2430 pound roller coaster starts from rest and is launched such that it crests a 105 ft high hill with a speed of 59 mph. The
    10·1 answer
  • Calculate the mass of material whose density is 0.798gcm and the mass of 25g ​
    9·1 answer
  • A ball is dropped from rest from the top of a building. What force is responsible for the downward motion of the ball?
    13·1 answer
  • Plz help me make a nice C-E-R for science I will give brainly for the best C-E-R
    11·1 answer
  • Can someone please answer my question please. thank you ❤️ ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!