The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg
Aspartame has the chemical formula C14H18N2O5
C = 12, H = 1, N = 14, O = 16
(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)
= 168 + 18 + 28 + 80
= 294 amu
(b) Mass of 1 molecule of aspartame = mole x molar mass
= 1 x 294
= 294 g
Converting 294 g to kg = 294/1000
= 0.294 kg
More on mole and molar mass can be found here: brainly.com/question/6613610
Answer:
21544 N
Explanation:
Let the atmospheric pressure be 101325 Pa
The side length of the cubic box:

![d = \sqrt[3]{V} = \sqrt[3]{0.051} = 0.371 m](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%5B3%5D%7BV%7D%20%3D%20%5Csqrt%5B3%5D%7B0.051%7D%20%3D%200.371%20m)
The area of the cubic box:

20 C = 20 + 273 = 293 K
180 C = 180 + 273 = 453 K
As the volume of the air inside the closed cube is not changed, assume the ideal gas law we have

Where P1 = 101325 Pa and T1 = 293K are the original atmospheric pressure and temperature. P2 and T2 = 453 are the new pressure and temperature after the cube gets heat up

The net force on each side of the box it its pressure times side area

Answer:
Explanation:
Given
Mass of alice 
Mass of bob 
Mass of beam 
Suppose fulcrum is at distance of d from bob thus From diagram
Equating torque i.e. torque of Bob,Alice and beam must cancel out each other to be balanced




Answer:
The horizontal component of the 70 N force = 35·√3 N
The vertical component of the 70 N force = 35 N
Explanation:
The magnitude of the given force, F = 70 N
The angle of inclination of the given force to the horizontal, θ = 30°
By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components,
, as follows;
The horizontal component of the given force = Fₓ = F × cos(θ)
Substituting the values, we have;
The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N
The vertical component of the given force =
= F × sin(θ)
Substituting the values, we have;
The vertical component of the 70 N force,
= 70 × sin(30°) = 35 N.