Consider the nuclear equation below. 239/94 Pu—-> X+ 4/2 He. What is X?
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Given :
Length , l = 59.8 m.
Breadth , b = 26.6 m.
Depth , d = 3.7 ft .
Density of water , .
To Find :
Mass of water in pool .
Solution :
First we will covert depth into m from ft .
For ,
So , volume of pool is :
We know , density is given by :
So ,
Putting given values in above equation :
Hence , this is the required solution.