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MatroZZZ [7]
3 years ago
10

Assume that the heat lost by the surface is gained by ethyl chloride. What enthalpies must you consider if you were to calculate

the final temperature of the surface
Chemistry
1 answer:
Ann [662]3 years ago
3 0

Answer:

Specific heat of ethyl chloride in gas and liquid phases, enthalpy of vaporization and specific heat of solid surface.

Explanation:

In order to determine the final temperature, the heat lost by the chloride needs to be found. This would require the specific heat in both phases and the enthalpy of vaporization. (you will use q=mc(delta)T and q=m(delta)H)

Then the energy gained by the surface needs to be found. This will require the specific heat in order to use the q=mc(delta)T equation.

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What role does the wire play in voltaic cell?
Triss [41]
<h3><u>Answer;</u></h3>

a) It allows electrons to flow from the anode to the cathode.

<h3><u>Explanation</u>;</h3>
  • <em><u>Voltaic cell is an electrochemical cell in which a spontaneous chemical reaction produces the flow of electrons</u></em>.
  • Electrons are produced by the oxidation reaction occurring at the anode. Electrons flow through the conducting wire from the anode to the cathode. At the cathode these electrons are used to reduce copper(II) ions to copper atoms.
  • <em><u>A conducting wire or a wire play connects the two electrodes allowing electrons to flow from the anode to the cathode</u></em>.
7 0
3 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
Ann and Carol each lift the timber with a force of 80 kg/m/s2. If they lift the timber a distance of 1.25 meters, how much work
Novosadov [1.4K]
Work is defined energy transferred from one to another. 
The formula for work done is work done = force x distance

So in our problem, force is equal to 80 kg/ m / s^2 and distance is equal to 1.25 meters. So plugging in our values will give us:

work done = 80 kg/ m/ s^2 * 1.25 m
= 100.00 J is the answer.
4 0
3 years ago
Recall rem = rad x q radiation weighting factor (q): the ability to transfer energy to the body 1 for photons 1 for electrons 2
tino4ka555 [31]

The biological risk for the first person than the second as a result of radiation weighting is 10 times.

<h3>What is radiation weighting factor?</h3>

As stated in the question, radiation weighting factor (q) is the ability to transfer energy to the body.

If radiation factor of proton = 2, and radiation factor of alpha particles = 20.

  • First person is exposed to alpha radiation = 20
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Risk of first person with respect to second person = 20/2 = 10 times higher

Learn more about radiation factor here: brainly.com/question/24039736

#SPJ4

6 0
2 years ago
Why are only certain colors absorbed by and emitted from an atom?
zavuch27 [327]
The way I would explain it is quite difficult to understand, so this is what Google says. "The wavelength (or equivalently, frequency) of the photon is determined by the difference in energy between the two states. These emitted photons form the element's spectrum. The fact that only certain colors appear in an element's atomic emission spectrum means that only certain frequencies of light are emitted." I hope this helped.
6 0
4 years ago
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