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MatroZZZ [7]
3 years ago
10

Assume that the heat lost by the surface is gained by ethyl chloride. What enthalpies must you consider if you were to calculate

the final temperature of the surface
Chemistry
1 answer:
Ann [662]3 years ago
3 0

Answer:

Specific heat of ethyl chloride in gas and liquid phases, enthalpy of vaporization and specific heat of solid surface.

Explanation:

In order to determine the final temperature, the heat lost by the chloride needs to be found. This would require the specific heat in both phases and the enthalpy of vaporization. (you will use q=mc(delta)T and q=m(delta)H)

Then the energy gained by the surface needs to be found. This will require the specific heat in order to use the q=mc(delta)T equation.

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A geologist is studying an area where stream erosion and deposition are the dominant surface processes. He notices that all of t
mixas84 [53]

Answer: A)

Explanation:

the deposition environment has changed from wind-dominated in the past to stream-dominated today.

7 0
3 years ago
1. If we have a reaction of Zn3PO4 and HCl, what would the products of this
Vladimir79 [104]

Answer:

1. The products of this reaction are ZnCl₂ and H₃PO₄.

2. 14.57 g.

Explanation:

<em>1. What would the products of this  reaction be?</em>

  • The balanced reaction between Zn₃(PO₄)₂ and HCl is represented as:

<em>Zn₃(PO₄)₂ + 6HCl → 3ZnCl₂ + 2H₃PO₄,</em>

It is clear that 1.0 mol of Zn₃(PO₄)₂ reacts with 6.0 mol of HCl to produce 3.0 mol of ZnCl₂ and 2.0 mol of H₃PO₄.

So, the products of this reaction are ZnCl₂ and H₃PO₄.

<em>2. If we produced 13.05 g of H₃PO₄, how many grams of  hydrochloric acid would be need to start with?​</em>

  • Firstly, we should get the no. of moles (n) of 13.05 grams of H₃PO₄:

n = mass/molar mass = (13.05 g)/(97.994 g/mol) = 0.1332 mol.

<u><em>Using cross-multiplication:</em></u>

6.0 mol of HCl needed to produce → 2.0 mol of H₃PO₄, from stichiometry.

??? mol of HCl needed to produce → 0.1332 mol of H₃PO₄.

∴ The no. of moles of HCl needed = (6.0 mol)(0.1332 mol)/(2.0 mol) = 0.3995 mol.

∴ The mass of HCl needed = n*molar mass = (0.3995 mol)(36.46 g/mol) = 14.57 g.

<em>So, the grams of  hydrochloric acid would be need to start with = 14.57 g.</em>

3 0
3 years ago
List six elements with only 1 electron in an s orbital
Verdich [7]

Answer:

Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1

Explanation:

When it comes to electron configuration and orbitals, it's important to first identify what exactly we are trying to identify. Below is a given example:

He1s^2

He=element

1=level

s=orbital

(exponent)^2=electrons

Looking at the periodic table, identify the alkali metal family on the periodic table, or group one elements:

Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1

Notice how each configuration has an exponent of 1, representative of a single electron in their s-orbital.

6 0
3 years ago
The correct lewis structure for COH2 contains how many covalent bonds?
VARVARA [1.3K]

Answer:

Four covalent bonds.

Explanation:

Hello,

In this case, given the attached picture in which you can find the Lewis dot structure for metanal (formaldehyde) we can see two C-H bonds and two C-O bonds via a double bond, thus, we can compute the type of each bond given the electronegativities of hydrogen, carbon and oxygen which are 2.1, 2.5 and 3.5 respectively:

C-H=2.5-2.1=0.4\\C-O=3.5-2.5=1.0

Thus, since both electronegativity difference are less 1.7 we infer that all of them are covalent, therefore, it has four covalent bonds, two C-H bonds and a double C-O bond.

Best regards-

8 0
3 years ago
Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct
kobusy [5.1K]

Answer:

B)−6,942 J /mol

Explanation:

At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:

ΔG = ΔH - TΔS

Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.

Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):

ΔG = ΔH - TΔS

ΔG = 25450J/mol - 298K×108.7J/molK

ΔG = -6942.6J/mol

Right solution is:

<h3>B)−6,942 J /mol</h3>

8 0
3 years ago
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