1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MrRa [10]
3 years ago
14

What is the gauge pressure in Pascals inside a honey droplet of a 0.1 cm diameter? Assume that air is surrounding this droplet a

nd the surface tension of honey is 0.052 N/m.
Give your answer to the nearest integer (do NOT use scientific notation).
Physics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure =  P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

Gauge pressure = 4γ / r

Gauge pressure = 4 (0.052) / (0.0005)

Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

You might be interested in
Which layer of the sun's atmosphere are you looking at when you look at me in image of the Sun
Hitman42 [59]
The answer is Photosphere.  The photosphere is the lowest layer<span> of the </span>solar<span> atmosphere. It is essentially the </span>solar<span> "surface" that </span>we see<span> when </span>we look<span> at the </span>Sun in "white" light.  It is <span>like a glowing fog, so at a distance, it </span>looks<span> solid, the same way a cloud looks solid from a distance.</span>
7 0
3 years ago
Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba
MakcuM [25]
At the very top of the peak and on the way down
7 0
3 years ago
Read 2 more answers
In an elastic collision, a 400-kg bumper car collides directly from behind with a second, identical bumper car that is traveling
kirza4 [7]

Answer:

v₁ = 3.5 m/s

v₂ = 6.4 m/s

Explanation:

We have the following data:

m₁ = mass of trailing car = 400 kg

m₂ = mass of leading car = 400 kg

u₁ = initial speed of trailing car = 6.4 m/s

u₂ = initial speed of leading car = 3.5 m/s

v₁ = final speed of trailing car = ?

v₂ = final speed of leading car = ?

The final speed of the leading car is given by the following formula:

v_2=\frac{2m_1}{m_1+m_2}u_1-\frac{m_1-m_2}{m_1+m_2}u_2\\\\v_2=\frac{(2)(400\ kg)}{400\ kg+400\ kg}(6.4\ m/s)-\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(3.5\ m/s)

<u>v₂ = 6.4 m/s</u>

The final speed of the leading car is given by the following formula:

v_1=\frac{m_1-m_2}{m_1+m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\\\v_1=\frac{400\ kg-400\ kg}{400\ kg + 400\ kg}(6.4\ m/s)+\frac{(2)(400\ kg)}{400\ kg+400\ kg}(3.5\ m/s)

<u>v₁ = 3.5 m/s</u>

4 0
3 years ago
Which of the following statements about the force on a charged particle due to a magnetic field are not valid?
Vinil7 [7]
The correct answer is "None of the above; all of these statements are valid." All the statements namely, it depends on the particle's charge, it depends on the strength of the external magnetic field, it depends on the particle's velocity, and it acts at right angles to the direction of the particle's motion are all valid. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
5 0
3 years ago
If an automobile engine delivers 42.0 hp of power, how much time will it take for the engine to do 6.20 â 105 j of work? (hint:
Elena L [17]
To be able to answer this item, we are to calculate the power that the machine could deliver from hp to kW. 

      (45 hp)(746 W/1 hp) = 33570 W

Power is the amount of energy delivered at a certain period. 

             t = (6.20 x 10^2 J)/ (33570 kJ/s)

             t = 0.01845 s
7 0
3 years ago
Other questions:
  • If the mass of a material is 104 grams and the volume of the material is 16 cm3, what would the density of the material be?
    6·1 answer
  • What is the pressure at the bottom<br> of a 2.50 m deep pool of water?
    8·1 answer
  • 8. A person with a mass of 15 kg is walking on a flat surface at a velocity of 5 m/s. What is the walker's momentum?
    5·1 answer
  • A solid disk and a thin-walled hoop each have a diameter of 8 cm. Both are released from rest at the same time at the top of a r
    7·1 answer
  • Two toddlers are fighting over a toy. Joey pulls the toy with a force of 8 N while Tommy pulls the toy with a force of 7.5 N. Wh
    11·1 answer
  • A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to
    12·1 answer
  • An object is moving in a straight line at constant speed. A resultant torce begins to act upon
    6·1 answer
  • What were the three factors that affected density
    9·1 answer
  • French jrnf;kwnb;vnkj2wert
    13·1 answer
  • The magnitude of the force associated with the gravitational field is constant and has a value f. A particle is launched from po
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!