Answer:
Explanation:
Given
Displacement is 
of Amplitude
i.e. 
, where A is maximum amplitude
Potential Energy is given by
Total Energy of SHM is given by
Total Energy=kinetic Energy+Potential Energy
Potential Energy is 
th of Total Energy
Kinetic Energy is 
of Total Energy
(c)Kinetic Energy is 
Answer:68m/s
Explanation:
Frequency=17Hz
Wavelength=4metre
Wave speed=frequency x wavelength
Wave speed =17 x 4
Wave speed =68m/s
Answer: The following statement is true about squall line thunderstorm development: <em><u>These often form ahead of the advancing front but rarely behind it because lifting of warm, humid air and the generation of a squall line usually occur in the warm sector ahead of an advancing cold front. Behind a cold front, the air motions are usually downward, and the air is cooler and drier.</u></em>
<em>An upper-level wave, accountable for the fabrication of a squall line, extend in front of and backside a cold front, the air backside the front is cold, steady and settling while the air ahead of the front is hot and co-seismic.</em>
So looking at the problem, you are going to want to start by finding a common denominator (1) in this case: yb, and combining like terms (2). You are then going to want to multiply both sides by (yb) as the reciprocal to the fractions (3).
1) 3x 6g
---- = ---
y b
2) 3xb 6gy
------ = -----
yb yb
3) 3xb 6gy
(yb) ------ = -----
yb yb
which becomes: 3xb = 6gy
So after this, things become much more simple, as all you have to do is isolate the (x), which can be done by dividing the entire equation by (3b).
3xb 6gy
----- = -----
3b 3b
where you will then find your answer of:
2gy
x = ----- (simplified by the GCM of 3)
b
