Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.20×106 N , one at an angle 19.0 ∘ west of north,
and the other at an angle 19.0 ∘ east of north, as they pull the tanker a distance 0.720 km toward the north.What is the total work done by the two tugboats on the supertanker?Express your answer in joules, to three significant figures.
1 answer:
Answer:
Explanation:
According to the question
net force F = 2.20×10^6 N
displacement
from figure , the horizontal forces are same in magnitude and opposite direction.
so , neglect these two forces.
we can take only vertical components of the force.
total force F' = F cos 19° + F cos 19°
= 2×F×cos 19° ................. (1
therefore , total work is
W = F'S
= (2F cos19)×S
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<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
Stress is defined as force per unit area and strain is defined as proportional deformation in a material.
The equation representing Young's Modulus is:
where,
Y = Young's Modulus
F = force exerted by the weight
l = length of wire
A = area of cross section
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Hence, the correct answer is Option b.
Answer:
v_average = 15 m / s
Explanation:
The average speed can be found in two ways,
* taking the distance traveled and divide it by the time spent
* taking the velocities in each time interval and then finding the weighted average by the time fraction
v_average = 1 / t_total ∑ vi ti
Let's apply this last equation
Total time is
t = t₁ + t₂
t = 10 + 10 = 20 min
v_average = 10/20 10 + 10/20 20
v_average = 10/2 + 20/2
v_average = 15 m / s