Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.20×106 N , one at an angle 19.0 ∘ west of north,
and the other at an angle 19.0 ∘ east of north, as they pull the tanker a distance 0.720 km toward the north.What is the total work done by the two tugboats on the supertanker?Express your answer in joules, to three significant figures.
1 answer:
Answer:
Explanation:
According to the question
net force F = 2.20×10^6 N
displacement
from figure , the horizontal forces are same in magnitude and opposite direction.
so , neglect these two forces.
we can take only vertical components of the force.
total force F' = F cos 19° + F cos 19°
= 2×F×cos 19° ................. (1
therefore , total work is
W = F'S
= (2F cos19)×S
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here's the solution,
The <em>radius</em> of the circle =<u> 3 km</u>
distance covered = <em>circumference</em> of the circle,
So, Circumference :
=》
=》
=》
(a). Distance covered by moving object is 18.84 km
(b). 0 km
now, Displacement of the object is 0 km, because displacement is the shortest distance from stating point to the destination, but the object returns back to the starting point, hence magnitude of displacement is 0.
Answer:
0.013N
Explanation:
m=0.04, v=4.4m/s, r=60
F=0.013 N